c plus plus langue
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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Question
hi need help code this in c plus plus langue a give a thumbs up
![Problem Description:
Display the sum of 2 polynomials.
(Sample) Sum of Polynomials:
f1 = 4x^3 + 3x^2
f2 = x^3 + 4x^2 + 3x - 2
+ 1
f3 = 5x^3 + 7x^2 + 3x - 1
Coding Specifications:
Validate coefficients. Range: -9.9.
Store coefficients as linear arrays.
Use modular programming design.
Refer to Prototypes for function definition.
Refer to Sample Dialog for I/O format.
Ask if user wants to Try Again.
Array Implementation:
f114]={ 1,0,3,4);
f2[4]={-2,3,4,1};
f3[4]={-1,3,7,5);
Function Prototypes:
void getCoef(int f(4]), string prompt);
void printFunc(int f[4], string msg);
void addFunc(int f1[4], int f2[4], int fB[4]);
SAMPLE DIALOG:
Enter coefficients for f1 (x0, x1, x2, x3):
1034
Enter coefficients for f1 (x0, x1, x2, x3):
-2341
f1 = 4x^3 + 3x^2
f2 = x^3 + 4x^2 + 3x - 2
+ 1
f3 = 5x^3 + 7x^2 + 3x - 1
Try Again(y/n)? n](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F705f62a2-7c80-4984-ae65-d2b3fd777cf9%2F852ec90d-2df0-4e46-8037-9df2cb5daa4a%2Fljz8mn8_processed.png&w=3840&q=75)
Transcribed Image Text:Problem Description:
Display the sum of 2 polynomials.
(Sample) Sum of Polynomials:
f1 = 4x^3 + 3x^2
f2 = x^3 + 4x^2 + 3x - 2
+ 1
f3 = 5x^3 + 7x^2 + 3x - 1
Coding Specifications:
Validate coefficients. Range: -9.9.
Store coefficients as linear arrays.
Use modular programming design.
Refer to Prototypes for function definition.
Refer to Sample Dialog for I/O format.
Ask if user wants to Try Again.
Array Implementation:
f114]={ 1,0,3,4);
f2[4]={-2,3,4,1};
f3[4]={-1,3,7,5);
Function Prototypes:
void getCoef(int f(4]), string prompt);
void printFunc(int f[4], string msg);
void addFunc(int f1[4], int f2[4], int fB[4]);
SAMPLE DIALOG:
Enter coefficients for f1 (x0, x1, x2, x3):
1034
Enter coefficients for f1 (x0, x1, x2, x3):
-2341
f1 = 4x^3 + 3x^2
f2 = x^3 + 4x^2 + 3x - 2
+ 1
f3 = 5x^3 + 7x^2 + 3x - 1
Try Again(y/n)? n
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