(c) Part of the parabola y = 2(x + 1)² from the point (0, 2) to the point (-1,0). (d) Counterclockwise around the perimeter of a triangle of area 3. Hint: If the curve C is a finite union of the smooth curves C₁,, Cn joining n | sds = [[! Σfds. i=1 Ci end to end then
(c) Part of the parabola y = 2(x + 1)² from the point (0, 2) to the point (-1,0). (d) Counterclockwise around the perimeter of a triangle of area 3. Hint: If the curve C is a finite union of the smooth curves C₁,, Cn joining n | sds = [[! Σfds. i=1 Ci end to end then
(c) Part of the parabola y = 2(x + 1)² from the point (0, 2) to the point (-1,0). (d) Counterclockwise around the perimeter of a triangle of area 3. Hint: If the curve C is a finite union of the smooth curves C₁,, Cn joining n | sds = [[! Σfds. i=1 Ci end to end then
This is Vector Calculus. Please answer thoroughly with clear answers and explanations. This is a 4 part question split into two different posts. PLEASE ONLY ANSWER PARTS C and D. Thank you
Calculus that deals with differentiation and integration of the vector field in three-dimensional Euclidean space. It deals with quantities that have both magnitude and direction.
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