(c) P(13.091 s x² s 35.172), where x² is a chi-squared rv with y = 23 The probability P(13.091 s x? s 35.172) is the area between x,? = 13.091 and x = 35.172. We are given degrees of freedom y = 23, so we have x„, 23² = 13.091 and x„, 23 Refer to the table of critical values for chi-squared distributions. For x, 23° = 13.091, search for the value closest to 13.091 in the row corresponding to v = 23. The value of a corresponding to this value is 22.302 Similarly, for x , 23 value of a corresponding to this value is a = 40.050 - 35.172. = 35.172, search for the value closest to 35.172 in the row corresponding to v = 23. The
(c) P(13.091 s x² s 35.172), where x² is a chi-squared rv with y = 23 The probability P(13.091 s x? s 35.172) is the area between x,? = 13.091 and x = 35.172. We are given degrees of freedom y = 23, so we have x„, 23² = 13.091 and x„, 23 Refer to the table of critical values for chi-squared distributions. For x, 23° = 13.091, search for the value closest to 13.091 in the row corresponding to v = 23. The value of a corresponding to this value is 22.302 Similarly, for x , 23 value of a corresponding to this value is a = 40.050 - 35.172. = 35.172, search for the value closest to 35.172 in the row corresponding to v = 23. The
A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
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Chapter1: Combinatorial Analysis
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Transcribed Image Text:(c) P(13.091 sx s 35.172), where x is a chi-squared rv with v = 23
The probability P(13.091 s x? s 35.172) is the area between x,
given degrees of freedom y = 23, so we have x, 2? = 13.091 and x, 2
2 = 13.091 and x. = 35.172. We are
2 = 35.172.
Refer to the table of critical values for chi-squared distributions. For x. 23
= 13.091, search for the value
closest to 13.091 in the row corresponding to v = 23. The value of a corresponding to this value is
a = 22.382
Similarly, for x, 23
value of a corresponding to this value is a = 46.059
2
= 35.172, search for the value closest to 35.172 in the row corresponding to v = 23. The
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