c) Now suppose L = 0.08 m and a point charge q = 30 µC is initially 0.03 m to the right of the line charge. If q is moved 0.02 m farther to the right and the change in its potential energy is +46.41 J what is the charge per unit length and total charge of the line charge?

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just c please. work for a and b are provided if it helps.

6. Consider a finite line charge with uniform charge density A and length L:
L
a) Using the following expression for electric potential
V =
In (1+z) = 2
X
dq
1
4πεο r
find the electric potential a distance x to the right of the line charge at the point P.
b) Show that if x >> L your answer to part a) looks like the electric potential of a point charge. The following might be
helpful:
-
●P
1
1
·2² +
2! 3!
2³
+..
for -1 << 1.
c) Now suppose L = 0.08 m and a point charge q = 30 µC is initially 0.03 m to the right of the line charge. If q is moved
0.02 m farther to the right and the change in its potential energy is +46.41 J what is the charge per unit length and total
charge of the line charge?
Transcribed Image Text:6. Consider a finite line charge with uniform charge density A and length L: L a) Using the following expression for electric potential V = In (1+z) = 2 X dq 1 4πεο r find the electric potential a distance x to the right of the line charge at the point P. b) Show that if x >> L your answer to part a) looks like the electric potential of a point charge. The following might be helpful: - ●P 1 1 ·2² + 2! 3! 2³ +.. for -1 << 1. c) Now suppose L = 0.08 m and a point charge q = 30 µC is initially 0.03 m to the right of the line charge. If q is moved 0.02 m farther to the right and the change in its potential energy is +46.41 J what is the charge per unit length and total charge of the line charge?
so
xd8
dV= Into (L-√+x)
so
V=
V=
V=
L
Št into
A dr
4G (L-r+x)
(2)
(-x) ln | 2+x-2)
ство
V=-_^ In
акво
ㅗ
AKE * {lax - In L+x}]
V=
X
ство
(b) for x>>2
x
Ltk
V = ARE ==/2
але х
so, L looks like
=
L
+
^ In (1+1/2)
ство
en (1+2=/=/=)
Q
а ток
It is very small so
en ( 1 += =/=/2) = = =/=/²2 - 12/17 (1/2) 2²+... ~ / / 2
← Answer to a)
• LA=Q
Q.ED
a point charge Q.
Transcribed Image Text:so xd8 dV= Into (L-√+x) so V= V= V= L Št into A dr 4G (L-r+x) (2) (-x) ln | 2+x-2) ство V=-_^ In акво ㅗ AKE * {lax - In L+x}] V= X ство (b) for x>>2 x Ltk V = ARE ==/2 але х so, L looks like = L + ^ In (1+1/2) ство en (1+2=/=/=) Q а ток It is very small so en ( 1 += =/=/2) = = =/=/²2 - 12/17 (1/2) 2²+... ~ / / 2 ← Answer to a) • LA=Q Q.ED a point charge Q.
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