(c) n=3, p=0.63, X=2 P (X) =

MATLAB: An Introduction with Applications
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Author:Amos Gilat
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P(X) = ?
The image contains a snippet from an educational platform's exercise on binomial probabilities. Below is a transcription and explanation suitable for an educational website:

---

**Progress Bar:**
- Part: 2 / 5

**Exercise:**
- Part 3 of 5

**Problem Statement:**
Calculate the probability for a binomial distribution with the following parameters:
- Number of trials (\( n \)): 3
- Probability of success on a single trial (\( p \)): 0.63
- Number of successes (\( X \)): 2

**Probability Calculation:**
\[ P(X) = \;[\text{Blank box for student input}] \]

---

### Explanation:

In this problem, you are asked to find the probability of achieving exactly 2 successes in 3 trials, with the probability of success on each trial being 0.63. This is a typical question involving the binomial probability formula:

\[ P(X = k) = \binom{n}{k} p^k (1-p)^{n-k} \]

Where:
- \( \binom{n}{k} \) is the binomial coefficient, calculated as \(\frac{n!}{k!(n-k)!}\).
- \( n \) is the total number of trials.
- \( k \) is the number of successes.
- \( p \) is the probability of success on each trial.

The student is expected to apply this formula to find \( P(X = 2) \) by substituting in the given values.
Transcribed Image Text:The image contains a snippet from an educational platform's exercise on binomial probabilities. Below is a transcription and explanation suitable for an educational website: --- **Progress Bar:** - Part: 2 / 5 **Exercise:** - Part 3 of 5 **Problem Statement:** Calculate the probability for a binomial distribution with the following parameters: - Number of trials (\( n \)): 3 - Probability of success on a single trial (\( p \)): 0.63 - Number of successes (\( X \)): 2 **Probability Calculation:** \[ P(X) = \;[\text{Blank box for student input}] \] --- ### Explanation: In this problem, you are asked to find the probability of achieving exactly 2 successes in 3 trials, with the probability of success on each trial being 0.63. This is a typical question involving the binomial probability formula: \[ P(X = k) = \binom{n}{k} p^k (1-p)^{n-k} \] Where: - \( \binom{n}{k} \) is the binomial coefficient, calculated as \(\frac{n!}{k!(n-k)!}\). - \( n \) is the total number of trials. - \( k \) is the number of successes. - \( p \) is the probability of success on each trial. The student is expected to apply this formula to find \( P(X = 2) \) by substituting in the given values.
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