// c) int sum = N; for (int i for (int j } } for } 0; i < 1000000; i++) { 1; j <= i; j++) { } for (int j 1; j <= i; j++) { sum += N; = sum += N; } = (int j sum += N; } cout << sum << endl; // d) vector list; for (int i = 1; i <= N * N; i++) { for (int j = 1; j <= N; j++) { list.push_back(i + j); 1; j <= i; j++) { = for (int i 1; i <= 2 * N; i++) { list.erase (list.begin() + list.size() - 1); } cout << "done!" << endl; answer: answer:
// c) int sum = N; for (int i for (int j } } for } 0; i < 1000000; i++) { 1; j <= i; j++) { } for (int j 1; j <= i; j++) { sum += N; = sum += N; } = (int j sum += N; } cout << sum << endl; // d) vector list; for (int i = 1; i <= N * N; i++) { for (int j = 1; j <= N; j++) { list.push_back(i + j); 1; j <= i; j++) { = for (int i 1; i <= 2 * N; i++) { list.erase (list.begin() + list.size() - 1); } cout << "done!" << endl; answer: answer:
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
Related questions
Question
please answer
![// c)
int sum = N;
for (int i = Ø; i < 1000000; i++) {
for (int j
1; j <= i; j++) {
}
for (int j
}
}
sum += N;
}
for (int j
=
}
=
sum += N;
=
sum += N;
1; j <= i; j++) {
}
cout << sum << endl;
1; j <= i; j++) {
// d)
vector<int> list;
for (int i = 1; i <= N * N; i++) {
for (int j = 1; j <= N; j++) {
list.push_back(i + j);
for (int i = 1; i <= 2 * N; i++) {
list.erase (list.begin() + list.size()
}
cout << "done!" << endl;
-
1);
answer:
answer:](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ffa25f1dd-a44a-4ace-ac61-e3b8d69dd121%2F1db9eb87-45ca-44bc-93ff-39e21f67decd%2Fulxstum_processed.png&w=3840&q=75)
Transcribed Image Text:// c)
int sum = N;
for (int i = Ø; i < 1000000; i++) {
for (int j
1; j <= i; j++) {
}
for (int j
}
}
sum += N;
}
for (int j
=
}
=
sum += N;
=
sum += N;
1; j <= i; j++) {
}
cout << sum << endl;
1; j <= i; j++) {
// d)
vector<int> list;
for (int i = 1; i <= N * N; i++) {
for (int j = 1; j <= N; j++) {
list.push_back(i + j);
for (int i = 1; i <= 2 * N; i++) {
list.erase (list.begin() + list.size()
}
cout << "done!" << endl;
-
1);
answer:
answer:
Expert Solution
![](/static/compass_v2/shared-icons/check-mark.png)
Step 1
(c) The answer is: N * 1000000 * (500000500000).
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