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(c) In a communication system the signal sent from point X to point Y arrives by two paths in parallel. Over each path the signal passes through two repeaters (in series). Each repeater in one path has a probability of failing (becoming an open circuit) of 0.005. This probability is 0.008 for each repeater on the other path. All repeaters fail independently of each other. Find the probability that the signal will

(c) In a communication system the signal sent from point X to point Y arrives by two paths in parallel. Over each path the signal passes through two repeaters (in series). Each repeater in one path has a probability of failing (becoming an open circuit) of 0.005. This probability is 0.008 for each repeater on the other path. All repeaters fail independently of each other. Find the probability that the signal will

A First Course in Probability (10th Edition)
A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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(c) In a communication system the signal sent from point X to point Y arrives by two paths in parallel. Over each path the signal passes through two repeaters (in series). Each repeater in one path has a probability of failing (becoming an open circuit) of 0.005. This probability is 0.008 for each repeater on the other path. All repeaters fail independently of each other. Find the probability that the signal will not arrive at point Y. Suppose the signal sent from point X to point Y arrives by two identical paths in parallel, in which each path has three repeaters; the first path has repeater R₁, linked to two other parallel repeaters R₂,and R3. The second path has identical arrangement as the first path with repeaters R4, R5 and R6. The probabilities of the repeaters failing (independently) are; p₁ = P(R₁) = 0.005, P2 = P(R₂) = P(R3) = P(R4) = 0.01, p3 = P(R5) = P(R) = 0.05. Find the probability that the signal will not arrive at point Y.
Transcribed Image Text:(c) In a communication system the signal sent from point X to point Y arrives by two paths in parallel. Over each path the signal passes through two repeaters (in series). Each repeater in one path has a probability of failing (becoming an open circuit) of 0.005. This probability is 0.008 for each repeater on the other path. All repeaters fail independently of each other. Find the probability that the signal will not arrive at point Y. Suppose the signal sent from point X to point Y arrives by two identical paths in parallel, in which each path has three repeaters; the first path has repeater R₁, linked to two other parallel repeaters R₂,and R3. The second path has identical arrangement as the first path with repeaters R4, R5 and R6. The probabilities of the repeaters failing (independently) are; p₁ = P(R₁) = 0.005, P2 = P(R₂) = P(R3) = P(R4) = 0.01, p3 = P(R5) = P(R) = 0.05. Find the probability that the signal will not arrive at point Y.
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