C (iii) Find the term in xy in the expansion of (x + 2y)(2y – 4x)(4 + 3y).

Q: 1) (a) Determine the simplest form of the expansion of (2x4 - 1) 4. 4x (b) Determine the coefficient…

A: Consider,(1) (a) Given,(2x4−4x1​)4use the binomial theorem formula to simplify the given…

Q: What is the coefficient of xy³ when (2y-x)° is expanded by the binomial theorem?

A:

Q: Which is the correct expansion of (x+4y)^3 using the binomial theorem?

A:

Q: 3 Find the term in x³ in the expansion of (x-3)8. b Hence, find the term in x³ in the expansion of…

A:

Q: The coefficient of x²y4z5 in the expansion of (3x+y+z)¹¹ is

A: The given expression is: (3x + y + z)11 To find: The coefficient of x2y4z5 in the expansion of (3x +…

Q: Find the coefficient of x3y2z3w in the expansion of(2x + 3y − 4z + w)9.

A: The given expansion is 2x+3y-4z+w9. We have to find the coefficient of x3y2z3w.

Q: Write the binomial expansion for (x+3)°. ..... (x + 3)° =D

A: Solution...

Q: In the expansion of (x + y)16 which term has the same coefficient as x14y2? O a. x12,4 Oc x3y14 O d.…

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Q: What is the rule for this pattern? (figure 1 is 1 block) Of(x)=n+2 Of(x) = 2n Of(x)=n-1 Of(x) = 2n-1

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Q: What is the result of this Lambda expression? (λ(x) 4 * 2x + 3x)  (2)

A: The lambda expression (λ(x) 4 * 2x + 3x) defines a function that takes a single argument ` x ` and…

Q: Compute the constant term in the expansion of (2x³ + ½)¹².

A:

Q: Compute the coefficent of x8    in the expansion of (3x -2)13

A: The given expression is,

Q: Find L-1 [.

A:

Q: 1. The coefficient of x³y³ in the expansion of (2x + 2y)¹⁰ is 10 2. The constant term in the…

A:

Q: (c) Find the term independent of x in the expansion of, 15 2 +

A:

Q: Consider the binomial theorem to expand (2x + 2y). What is the coefficient of the x²y² term? You…

A: To expand: 2x+2y4 using binomial theorem.   Also find the coefficient of the x2y2 term.

Q: 10 Which term of the expansion of (x²+4) ¹º contains x 20 Term number contains x 20

A:

Q: 2. (a) Given that (2 + x)" (1-x)" =+ pa³+qx²+7x+s, determine the values of P.4.9, and s. (b) Without…

A: Step 1: Step 2: Step 3: Step 4:

Q: 1+ 3k 1- 3k] 1 – 3k 1+3k 2 - prove that AK: 2 1 For A : -1 -

A: Given, A=2-1-12   ...i    ....(i)  We need to show that Ak=121+3k1+3k1+3k1+3k    ...ii     Now, A…