A company claims that the mean monthly residential electricity consumption in a certain region is more than 880 kiloWatt-hours (kWh). You want to test this claim. You find that a random sample of 60 residential customers has a mean monthlyconsumption of 920 kWh. Assume the population standard deviation is 129 kWh. At a = 0.01, can you support the claim? Complete parts (a) through (e).(a) Identify Ho and H.. Choose the correct answer below.O A. Ho: u= 880 (claim)ΥΒ. H: μs 880H:u#880Ha:u> 880 (claim)O C. Ho: u> 920 (claim)Ο D. Hλ: μ5 920H: us 920Ha:u>920 (claim)O E. Ho: u> 880 (claim)H:us 880OF. Ho: H=920Ha:u#920 (claim)(b) Find the critical value(s) and identify the rejection region(s). Select the correct choice below and fill in the answer box within your choice. Use technology.(Round to two decimal places as needed.)O A. The critical values are +B. The critical value is 2.33Identify the rejection region(s). Select the correct choice below.O A. The rejection region isz<2.33.YB. The rejection region is z> 2.33.O C. The rejection regions are z< -2.33 and z>2.33(c) Find the standardized test statisuc. Use technology.The standardized test statistic is z =.(Round to two decimal places as needed.)

Given that Sample size n =60 Sample mean =920 Population standard deviation =129

Answered: (c) Find the standardized test…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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(c) Find the standardized test statisuc. Use technology. The standardized test statistic is z=. (Round to two decimal places as needed.)