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(c) Find the average rate of change for f(r) on the interval (6,6.001]. (Note: h = 6.001 – 6 = 0.001) %3D Answer: c to determine what the average (d) Over the interval (6, 6+ h, use parts a - rate of change is converging to as h0. Answer: f(r+h)-f(r) (e) Find the simplified difference quotient for f(r) at r = 6.

(c) Find the average rate of change for f(r) on the interval (6,6.001]. (Note: h = 6.001 – 6 = 0.001) %3D Answer: c to determine what the average (d) Over the interval (6, 6+ h, use parts a - rate of change is converging to as h0. Answer: f(r+h)-f(r) (e) Find the simplified difference quotient for f(r) at r = 6.

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Please help me answer this multi part question !
3 5. Answer the following questions for the function f(x) (a) Find the average rate of change for f(r) on the interval [6,6.1]. (Note: h = 6.1 – 6 = 0.1) fa) Answer: (b) Find the average rate of change for f(x) on the interval [6,6.01]. (Note: h = 6.01 - 6 = 0.01) Answer:
Transcribed Image Text:3 5. Answer the following questions for the function f(x) (a) Find the average rate of change for f(r) on the interval [6,6.1]. (Note: h = 6.1 – 6 = 0.1) fa) Answer: (b) Find the average rate of change for f(x) on the interval [6,6.01]. (Note: h = 6.01 - 6 = 0.01) Answer:
(c) Find the average rate of change for f(r) on the interval (6,6.001]. (Note: h = 6.001 –6 = 0.001) Answer: (d) Over the interval [6, 6+ h, use parts a - c to determine what the average rate of change is converging to as h0. Answer: f(x+ h)-f(x) (e) Find the simplified difference quotient for f(r) at r = 6. Answer: f (x + h) - f(x) for f(r) at (f) Determine the instantaneous rate of change lim h 0 T = 6. (Note: This is the slope of the tangent line to f(x) at x = 6.) Answer: (g) Write the equation of the tangent line to f(r) at r = 6. Answer:
Transcribed Image Text:(c) Find the average rate of change for f(r) on the interval (6,6.001]. (Note: h = 6.001 –6 = 0.001) Answer: (d) Over the interval [6, 6+ h, use parts a - c to determine what the average rate of change is converging to as h0. Answer: f(x+ h)-f(x) (e) Find the simplified difference quotient for f(r) at r = 6. Answer: f (x + h) - f(x) for f(r) at (f) Determine the instantaneous rate of change lim h 0 T = 6. (Note: This is the slope of the tangent line to f(x) at x = 6.) Answer: (g) Write the equation of the tangent line to f(r) at r = 6. Answer:
Expert Solution
Part(a)

NOTE: Refresh your page if you can't see any equations.

.

f\left(x\right)=\frac{3}{x}

on the interval [6,6.1], the average rate of change is given by

m=\frac{f\left(6.1\right)-f\left(6\right)}{6.1-6}

m= \frac{\frac{3}{6.1}-\frac{3}{6}}{6.1-6}

m= \frac{\frac{3}{6.1}-\frac{1}{2}}{0.1}

m= \frac{-0.0081967213}{0.1}

m= -\frac{0.0081967213 }{0.1}

m={\color{Red} -0.081967}

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