(c) Find (or estimate) the P-value. Sketch the sampling distribution and show the area corresponding to the P-value. Recall that based on our alternative hypothesis, H₁: > 85, we are conducting a right-tailed test. The P-value for a right-tailed test is P(Z > z). Because the table of areas of a standard normal distribution provides left-tailed areas, to find the right-tailed area, subtract the left-tailed area from 1. In other words, the right-tailed area is P(Z > z) = 1 - P(Z < zz). Use the table of areas of a standard normal distribution to find the P-value corresponding to z= 1.92. (Round your answers to four decimal places.) P-value = P(Z > 1.92) = 1 - P(Z < 1.92) = 1-

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(c) Find (or estimate) the P-value. Sketch the sampling distribution and show the area corresponding to the P-value.
Recall that based on our alternative hypothesis, H₁: > 85, we are conducting a right-tailed test. The P-value for a right-tailed test is P(z > Zx).
Because the table of areas of a standard normal distribution provides left-tailed areas, to find the right-tailed area, subtract the left-tailed area from 1.
In other words, the right-tailed area is P(Z > z) = 1 - P(Z < z).
Use the table of areas of a standard normal distribution to find the P-value corresponding to z = 1.92. (Round your answers to four decimal places.)
P-value = P(Z > 1.92)
= 1 P(Z < 1.92)
= 1 -
Transcribed Image Text:(c) Find (or estimate) the P-value. Sketch the sampling distribution and show the area corresponding to the P-value. Recall that based on our alternative hypothesis, H₁: > 85, we are conducting a right-tailed test. The P-value for a right-tailed test is P(z > Zx). Because the table of areas of a standard normal distribution provides left-tailed areas, to find the right-tailed area, subtract the left-tailed area from 1. In other words, the right-tailed area is P(Z > z) = 1 - P(Z < z). Use the table of areas of a standard normal distribution to find the P-value corresponding to z = 1.92. (Round your answers to four decimal places.) P-value = P(Z > 1.92) = 1 P(Z < 1.92) = 1 -
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