C, (µF) C1= 1.0 Q, (µC) V, E, (Volts) (Joules) C2 C2= 2.0 B C3= 3.0 C4= 4.0 Cs= 5.0 Ce= 6.0 %23 C7 Cr= 7.0 CAB= 10.0

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ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
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For the circuit diagram shown below, complete the given C-Q-V-E table. The potential difference applied across terminals A and B is 10.0 Volts

с,
Q,
v,
E,
(µF)
Ci= 1.0
(Volts) (Joules)
(µC)
C4
C2= 2.0
B
C3= 3.0
C4= 4.0
Cs= 5.0
Ce= 6.0
Cr= 7.0
CAB=
10.0
A,
Transcribed Image Text:с, Q, v, E, (µF) Ci= 1.0 (Volts) (Joules) (µC) C4 C2= 2.0 B C3= 3.0 C4= 4.0 Cs= 5.0 Ce= 6.0 Cr= 7.0 CAB= 10.0 A,
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