1.2 (c) electron capture by molybdenum-93O 93Мо -924242О 9342Mo + e →0.9341 NbO 93Мо42931e+ 43->934He + 40 Zr89Mo42 (d) positron emission by phosphorus-282815iet28S16O 28P +1528eSi->1428ie+ SiHe + 15 Al281514281524

->From electron capture atomic number decreases by one unit. ->From positron emission atomic…

Answered: (c) electron capture by molybdenum-93 O…

(c) electron capture by molybdenum-93 O 93 je+2 Nb Mo + _¡e → Nb ie+ Te He + 20 Zr Мо > 42 O 93 42 93 41 O 93 Mo → 42 93 43 O 93 Мо - 42 4 89

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Question

1.2

(c) electron capture by molybdenum-93
O 93
Мо -
92
42
42
О 93
42
Mo + e →
0.
93
41 Nb
O 93
Мо
42
93
1e+ 43
->
93
4
He + 40 Zr
89
Mo
42

(d) positron emission by phosphorus-28
28
15
iet
28
S
16
O 28
P +
15
28
e
Si
->
14
28
ie+ Si
He + 15 Al
28
15
14
28
15
24

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