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C = eir. an 2 Pi B = eiB A = eia Given this circle, prove arg( (B - A)/(C - A) ) = (1/2) arg( C/B) %3D

C = eir. an 2 Pi B = eiB A = eia Given this circle, prove arg( (B - A)/(C - A) ) = (1/2) arg( C/B) %3D

Elementary Geometry For College Students, 7e
Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
SectionP.CT: Test
Problem 1CT
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C = e*Y. an 2 Pi B = eiB A = eia Given this circle, prove arg( (B - A)/(C - A) ) = (1/2) arg( C/B) %3D
Transcribed Image Text:C = e*Y. an 2 Pi B = eiB A = eia Given this circle, prove arg( (B - A)/(C - A) ) = (1/2) arg( C/B) %3D
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