Sleep Time A person read that the average number of hours an adultsleeps on Friday night to Saturday morning was 7.1 hours. The researcher feelsthat college students do not sleep 7.1 hours on average. The researcherrandomly selected 16 students and found that on average they slept 8.1 hours.The standard deviation of the sample is 1.2 hours. At a=0.10, is there enoughevidence to say that college students do not sleep 7.1 hours on average?Assume that the population is approximately normally distributed. Use thecritical value method and tables. (c) Compute the test value. Always round t score values to three decimal places.t =

Given that Sample size = n = 16 Sample standard deviation = s = 1.2Null and alternative hypothesis H0 : μ = 7.1 H1 : μ ≠ 7.1 Test statistic ( t ) t = ( x̄ - μ )/(s/√(n)) = ( 8.1 - 7.1 ) / ( 1.2/√16 ) = 3.333

Answered: (c) Compute the test value. Always…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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r= 0.5, Exy = 120, Ex² = 90, o, = 8 where x and y are deviation from arithmetic average. Find the numher of items.
%3D A population of N= 5 scores has EX= 20 and EX² = 100. For this population, what is the value of SS?
Use the formula for finding a zz-score to determine the missing value in the following table. Round your answer to two decimal places, if necessary. IZ -2.33 X 26.40 н 40.3 σ
College tuition: The mean annual tuition and fees for a sample of 14 private colleges in California was $35,750 with a standard deviation of $7650. A dotplot shows that it is reasonable to assume that the population is approximately normal. Can you conclude that the mean tuition and fees for private institutions in California differs from $35,000 ? Use the a=0.10 level of significance and the P-value method with the TI-84 Plus calculator. Part 1 of 5
The brand manager for a brand of toothpaste must plan a campaign designed to increase brand recognition. He wants to first determine the percentage of adults who have heard of the brand. How many adults must he survey in order to be 90% confident that his estimate is within six percentage points of the true population percentage? Complete parts (a) through (c) below. a) Assume that nothing is known about the percentage of adults who have heard of the brand. n = 188 (Round up to the nearest integer.) b) Assume that a recent survey suggests that about 82% of adults have heard of the brand. n = 111 (Round up to the nearest integer.) c) Given that the required sample size is relatively small, could he simply survey the adults at the nearest college? OA. No, a sample of students at the nearest college is a cluster sample, not a simple random sample, so it is very possible that the results would not be representative of the population of adults. OB. No, a sample of students at the nearest…
q16
I need help with the first question: Find the z-score value associated with a guess of 38.
What is (b) p(z>-0.15) = ? Answer choices are .3945, -1,04,.5596,.6055,.4404
P(-2.4<Z<1.5) = ?
Find the z-score corresponding to a score of X=50. u=60 and o=5 u=45 and o=5 u=40 and o=5 u=37 and o=5 u=59 and o=5
Carmen and Rosanna are two employees in an electronics store. The store manager has put an emphasis on increasing the number of applications for the store credit card. The manager randomly selected 24 weeks for each employee and recorded the number of completed applications for each week, which is provided in the samples below. Each employee completed 21 applications in one of the weeks selected. Use Excel to calculate each employee's z-score for completing 21 applications. Round your answers to two decimal places. Carmen Rosanna11 56 1115 613 185 1114 1416 521 208 1110 97 1416 1513 1310 619 2118 95 1817 310 126 1712 1214 419 1017 8
find the value represented by z-score of 2.043, given u=63 and o=4.25

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