(c) Compute the double sum Ei-1 E}=1i²/(5+ j').

Q: Let ƒ(x) = (x³ + 4x + 6) ³ f'(x) = 9x¹ + 12x² f'(1) = 2541 X OF

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Q: Differentiate: f(x) = 2ª + e² + log, 5 f'(x) = 2" In 2+ e² A 1 ® f'(x)= 2" +e² + : 1 © f'(x)= 2" +…

A:

Q: By using the substitution u = x3", ir

A: Given, by using the substitution u=x3n, then   To find:   (1).   ∫nx3n-1ex3nex3n+8dx   (2).…

Q: Estimate n such that V * log(x) dx – T₁| < 10-8. Tn

A: for the function f(x)=logx  To find the value of n so that the error bound in trapezoidal and…

Q: s(t) = 1/t^3;  (-6 , -1/216) s'(6)= ?

A: Given: s(t)=1t3−6&lt;t&lt;−1216s'(6)=?

Q: f(x) = ln(cos3(2x+1)5)     f'(x) = ?

A: Given that f(x) = ln(cos3(2x+1)5)

Q: Solve the intial value problem f'(x) = 7x (x6-4) withf (I/6)=0.

A:

Q: ) Integrate from 9 to 13 the function: ( 1/ (x^2 + 6x) ). Calculate a floating-point value. ans:1

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Q: Find f'(x). f(x)= 4 Inx + e× − 5x² - f'(x) = [

A:

Q: Given the function f(x)= e^x/(1+2x)^2, compute f’(1).

A: Given the function f(x)=ex(1+2x)2, compute f'(1).

Q: f (x) = arctan(e") ad f'(-1) =? find %3D 28 - O A) 1/(e+e3) O B) (e2)/(1+e2) (e2)/(1+e) O D) e/(1+e)…

A: Explanation of the solution is given below....

Q: Find the polynomial of degree 9 (centered at zero) that best approximates f(x)=ln(x^(3)+5). a.)…

A: To find the Taylor's polynomial of a function f(x) at x=c, use the following formulae.…

Q: d dx f(x) = ex, f(0) = 8.

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Q: Find f'(x). f(x) = 2 In (7 + 2x²) f'(x)=|

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Q: Differentiate x *. Hence find [x(2+ x)e* dx.

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Q: 2) dx -

A: We will solve the integration by the substitution, t = ex

Q: 3/4 iv) L'(- 's² – s +1'

A:

Q: f(x)= 7tan-1(5sin(4x)) f'(x)=?

A: We have to find the derivative of the given function f(x)= 7tan-1(5sin(4x)).

Q: 2x + 3 f(x) = In %3D 7r – 7 f'(x) =

A:

Q: Let f(x) = 3x In f'(x) = 3x1 + 15x1 In(a) f'(e?)

A: We have to solve

Q: Let 6х — 8 - f(x) = ln 5x + 4 f' (x) =

A:

Q: Find f'(z) of f(z) = Log(z2i).

A: Given complex function is  f(z)=log(z2i)

Q: Find F'(x). F'(x) = F(x) = x + 5 [**5 X (4t + 9) dt

A: To find .

Q: 15) S secx * ln(tanx + secx) dx 15) ſ

A: we have to evaluate Now use the method of substitution Hence the integration becomes

Q: 9 – cosh a f(x) = 9 + cosh a

A:

Q: Solve for k:  y(t) = y(0) * e^(kt* (1-t/p) )  (we know that y(0)=P/10)

A: We have given yt=y0·ekt·1-tp,  y0=p10 By dividing both sides of the equation by y(0), yty0=ekt·1-tp…

Q: (2| | 2 | + 2 ਗਿਆ ਹੈ 3.॥ dx

A:

Q: e SİY

A: answer is in next step

Q: g(x) = "In(5 + t?) dt Ji

A: