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c) An organic compound with molecular formula C3H14O4 following spectral data : exhibited the (i) MS : m/z = 174, 129, 101 (üi) IR : 1736 cm¬1, 1095 cm¬1 (üi) 'H NMR : 8 = 1-29 (t), 2-61 (s), 4-19 (q) ppm (iv) 13C NMR : 8 = 10-13, 20-89 (DEPT inverted), 60-01, 171-09 ppm

c) An organic compound with molecular formula C3H14O4 following spectral data : exhibited the (i) MS : m/z = 174, 129, 101 (üi) IR : 1736 cm¬1, 1095 cm¬1 (üi) 'H NMR : 8 = 1-29 (t), 2-61 (s), 4-19 (q) ppm (iv) 13C NMR : 8 = 10-13, 20-89 (DEPT inverted), 60-01, 171-09 ppm

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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(c) An organic compound with molecular C3H1404 following spectral data : formula exhibited the (i) MS : m/z = 174, 129, 101 (ü) IR : 1736 cm¬1, 1095 cm¬1 (üi) 'H NMR : 2-61 (s), 8 = 1-29 (t), 4-19 (q) ppm (iv) 13 C NMR: 8 = 10-13, 20-89 (DEPT inverted), 60-01, 171-09 ppm Determine the structure of the compound with justification for the data
Transcribed Image Text:(c) An organic compound with molecular C3H1404 following spectral data : formula exhibited the (i) MS : m/z = 174, 129, 101 (ü) IR : 1736 cm¬1, 1095 cm¬1 (üi) 'H NMR : 2-61 (s), 8 = 1-29 (t), 4-19 (q) ppm (iv) 13 C NMR: 8 = 10-13, 20-89 (DEPT inverted), 60-01, 171-09 ppm Determine the structure of the compound with justification for the data
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