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c) A simple three-phase power system is shown in the Figure 2. Assume that the ratings of the various devices in this system are as follows: Generator G,: 250 MVA, 13.8 kV, R = 0.1 pu, X = 1.0 pu. Generator G,: 500 MVA, 20.0 kV, R = 0.1 pu, X =1.2 pu. Generator G3: 250 MVA, 13.8 kV, R = 0.15 pu, X = 1.0 pu. • Transformer T,: 250 MVA, 13.8/240 kV, R = 0.01 pu, X = 0.10 pu. • Transformer T,: 500 MVA, 20.0/240 kV, R = 0.01 pu, X = 0.08 pu. • Transformer T3: 250 MVA, 13.8/240 kV, R = 0.01 pu, X = 0.10 pu. • Each Line: R = 8 N, X = 40 Q. Region 1 Region 2 Region 3 AY Region 4 Figure 2 Convert this power system to per-unit on a base of 500 MVA at 20 kV at generator G2 and draw the per-unit per-phase equivalent circuit of this system.

c) A simple three-phase power system is shown in the Figure 2. Assume that the ratings of the various devices in this system are as follows: Generator G,: 250 MVA, 13.8 kV, R = 0.1 pu, X = 1.0 pu. Generator G,: 500 MVA, 20.0 kV, R = 0.1 pu, X =1.2 pu. Generator G3: 250 MVA, 13.8 kV, R = 0.15 pu, X = 1.0 pu. • Transformer T,: 250 MVA, 13.8/240 kV, R = 0.01 pu, X = 0.10 pu. • Transformer T,: 500 MVA, 20.0/240 kV, R = 0.01 pu, X = 0.08 pu. • Transformer T3: 250 MVA, 13.8/240 kV, R = 0.01 pu, X = 0.10 pu. • Each Line: R = 8 N, X = 40 Q. Region 1 Region 2 Region 3 AY Region 4 Figure 2 Convert this power system to per-unit on a base of 500 MVA at 20 kV at generator G2 and draw the per-unit per-phase equivalent circuit of this system.

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
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c) A simple three-phase power system is shown in the Figure 2. Assume that the ratings of the various devices in this system are as follows: Generator G,: 250 MVA, 13.8 kV, R = 0.1 pu, X = 1.0 pu. Generator G2: 500 MVA, 20.0 kV, R = 0.1 pu, X =1.2 pu. Generator G3: 250 MVA, 13.8 kV, R = 0.15 pu, X = 1.0 pu. • Transformer T;: 250 MVA, 13.8/240 kV, R = 0.01 pu, X = 0.10 pu. Transformer T,: 500 MVA, 20.0/240 kV, R = 0.01 pu, X = 0.08 pu. • Transformer T3: 250 MVA, 13.8/240 kV, R = 0.01 pu, X = 0.10 pu. • Each Line: R = 8 N, X = 40 Q. Region 1 Region 2 Region 3 G, G2 YO AY Region 4 Figure 2 Convert this power system to per-unit on a base of 500 MVA at 20 kV at generator G, and draw the per-unit per-phase equivalent circuit of this system.
Transcribed Image Text:c) A simple three-phase power system is shown in the Figure 2. Assume that the ratings of the various devices in this system are as follows: Generator G,: 250 MVA, 13.8 kV, R = 0.1 pu, X = 1.0 pu. Generator G2: 500 MVA, 20.0 kV, R = 0.1 pu, X =1.2 pu. Generator G3: 250 MVA, 13.8 kV, R = 0.15 pu, X = 1.0 pu. • Transformer T;: 250 MVA, 13.8/240 kV, R = 0.01 pu, X = 0.10 pu. Transformer T,: 500 MVA, 20.0/240 kV, R = 0.01 pu, X = 0.08 pu. • Transformer T3: 250 MVA, 13.8/240 kV, R = 0.01 pu, X = 0.10 pu. • Each Line: R = 8 N, X = 40 Q. Region 1 Region 2 Region 3 G, G2 YO AY Region 4 Figure 2 Convert this power system to per-unit on a base of 500 MVA at 20 kV at generator G, and draw the per-unit per-phase equivalent circuit of this system.
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