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c) 2x+1 Q5: A circular torus (i.e. a ring-doughnut shape) in which the overall diameter of the whole shape is D = 2R and the diameter of the ring is d = 2r has the total surface area A = A(R,r) = 4n²Rr and the volume V = V(R,r) = 2n²Rr². By manipulating these formulae into appropriate alternative forms, and then evaluating these with the given values (&n = 3.142), determine; a) R (to 2 dec.pl.) when A = 52.082m? &r = 0.319m, b) d (in Sci.Not. to 3 sig.dig.) when V = 1.26 x 10"m & D = 6.19 x 10°m.

c) 2x+1 Q5: A circular torus (i.e. a ring-doughnut shape) in which the overall diameter of the whole shape is D = 2R and the diameter of the ring is d = 2r has the total surface area A = A(R,r) = 4n²Rr and the volume V = V(R,r) = 2n²Rr². By manipulating these formulae into appropriate alternative forms, and then evaluating these with the given values (&n = 3.142), determine; a) R (to 2 dec.pl.) when A = 52.082m? &r = 0.319m, b) d (in Sci.Not. to 3 sig.dig.) when V = 1.26 x 10"m & D = 6.19 x 10°m.

Algebra and Trigonometry (6th Edition)
Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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Q5: A circular torus (i.e. a ring-doughnut shape) in which the overall diameter of the whole shape is ? = 2? and the diameter of the ring is ? = 2? has the total surface area ? = ?(?, ?) = 4?2?? and the volume ? = ?(?, ?) = 2?2??2. By manipulating these formulae into appropriate alternative forms, and then evaluating these with the given values (&? = 3.142), determine; a) ? (to 2 dec.pl.) when ? = 52.082m2 & ? = 0.319m, b) ? (in Sci.Not. to 3 sig.dig.) when ? = 1.26 × 108m3 & ? = 6.19 × 104m.
l 48 LTE 07:36 23% O A 1-xythos.content.blackboardcdn.com C 2 of 2 Q1: Simplify the following expressions; a) 2(х + 1) — 3(2 — х) b) x(2у - 3) - Зу(1-х) c) 3x(x – 2) – 2(x – 1)(x +3) Q2: Simplify the following expressions, and determine any value(s) of the variable(s) for which the expressions are not defined; 2x-31 a) 3+2x x+1 2x+1 c) x+1 3y-2 y+1 Q3: Factorise the following quadratics by means of the quadratic algorithm, and hence find their roots; a) x2 - 9x + 20 b) x? - 14x + 24 c) 2x? + 5x – 3 Q4: Solve the following equations giving your answer in an exact form, and if this is not a rational number also to 3 dec.pl. accuracy; a) 2(x + 1) – 3(2 - x) = 0 b) Зx(х — 2) - 2(х - 1)(х + 3) 30 3+2x 4x c) = 3 2x+1 x+1 Q5: A circular torus (i.e. a ring-doughnut shape) in which the overall diameter of the whole shape is D = 2R and the diameter of the ring is d = 2r has the total surface area A = A(R,r) = 4n²Rr and the volume V = V(R,r) = 2n²Rr². By manipulating these formulae into appropriate alternative forms, and then evaluating these with the given values (& = 3.142), determine; a) R (to 2 dec.pl.) when A = 52.082m² & r = 0.319m, b) d (in Sci.Not. to 3 sig.dig.) when V = 1.26 x 10 m³ & D = 6.19 x 10*m. After marking, your marks and any comments will immediately be available to you in 'My Grades', and after all marking is complete a summary for the whole group of the results on this assignment and the current overall totals will be published.
Transcribed Image Text:l 48 LTE 07:36 23% O A 1-xythos.content.blackboardcdn.com C 2 of 2 Q1: Simplify the following expressions; a) 2(х + 1) — 3(2 — х) b) x(2у - 3) - Зу(1-х) c) 3x(x – 2) – 2(x – 1)(x +3) Q2: Simplify the following expressions, and determine any value(s) of the variable(s) for which the expressions are not defined; 2x-31 a) 3+2x x+1 2x+1 c) x+1 3y-2 y+1 Q3: Factorise the following quadratics by means of the quadratic algorithm, and hence find their roots; a) x2 - 9x + 20 b) x? - 14x + 24 c) 2x? + 5x – 3 Q4: Solve the following equations giving your answer in an exact form, and if this is not a rational number also to 3 dec.pl. accuracy; a) 2(x + 1) – 3(2 - x) = 0 b) Зx(х — 2) - 2(х - 1)(х + 3) 30 3+2x 4x c) = 3 2x+1 x+1 Q5: A circular torus (i.e. a ring-doughnut shape) in which the overall diameter of the whole shape is D = 2R and the diameter of the ring is d = 2r has the total surface area A = A(R,r) = 4n²Rr and the volume V = V(R,r) = 2n²Rr². By manipulating these formulae into appropriate alternative forms, and then evaluating these with the given values (& = 3.142), determine; a) R (to 2 dec.pl.) when A = 52.082m² & r = 0.319m, b) d (in Sci.Not. to 3 sig.dig.) when V = 1.26 x 10 m³ & D = 6.19 x 10*m. After marking, your marks and any comments will immediately be available to you in 'My Grades', and after all marking is complete a summary for the whole group of the results on this assignment and the current overall totals will be published.
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