C, = 0.9167 + (2.577 × 10 *)T – (3.974 × 10 ")T² in kJ/kg-K. temperature reaches 927°C. The specific heat of air varies with temperature as Find the change of internal energy in kJ/kg. [ans: 718.1] temperature of 27°C receives heat Air with at constant volume until the %3D a. b. Find the change of enthalpy in kJ/kg. [ans: 976.4]

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TOPIC: THERMODYNAMICS - PROCESSES OF GASES

temperature reaches 927°C. The specific heat of air varies with temperature as
= 0.9167 + (2.577 × 10 *)T – (3.974 × 10 " )T² in kJ/kg-K.
a
temperature
of
27°C receives heat
1. Air with
at
constant
volume
until the
C, =
Find the change of internal energy in kJ/kg. [ans: 718.1]
a.
Find the change of enthalpy in kJ/kg. [ans: 976.4]
Transcribed Image Text:temperature reaches 927°C. The specific heat of air varies with temperature as = 0.9167 + (2.577 × 10 *)T – (3.974 × 10 " )T² in kJ/kg-K. a temperature of 27°C receives heat 1. Air with at constant volume until the C, = Find the change of internal energy in kJ/kg. [ans: 718.1] a. Find the change of enthalpy in kJ/kg. [ans: 976.4]
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