c' = 0 kPa 4'=30° 2m Y = 17 kN/m³ moist Ysa 19 kN/m³ WT ✓ 2m WT ☑ 7m

Given Y = 10 kn/m^3 Find Fh, Fv, horizontal distance of Fv from A

ANSWER KEY: D= 51.8319m∆h= 13.5430mElev Sta. A= 70.8530m

1. Determine the magnitude and direction of the resultant. substitute: F=2060, B= 465, D=72, E= 22 *300KN F+6 kN D° 12 E 200KN B+2_kN 3. in

W=1090 KN/m

Take that w0w0w_0 = 4.8 kN/mkN/m.

A pipe of Aluminum alloy is subjected to a tensile force F along its longitudinal axis. The pipe has an initial length of 1.2 m, an initial thickness t=1 mm and an initial outer diameter do= 10 mm. The mechanical properties of the alloy are: Modulus of Elasticity E = 75 GPa Yield stress YS = 350 MPa If a force F=12 kN is applied to the pipe, the length of the pipe becomes L=1.2282 m. Determine the permanent length of the pipe after removing the force. do F

Q2/ Arwana canal with rectangular cross section. The wall of the channel (4-2) has a water depth of 0.4 m. The amount of water that flows inside the canal is 360 m within two minutes. The slope changes to become the horizontal canal and the water level in it was 35 m. Will ahydraulic jump occurwhen the slope changes and why? 35 35 34.5 B=2y 0.4

Q.>> A Rectangular channel ( = 0:011) 18 m wide to Carry water at The slope f the channel ds 0.00078 (à) Determine the Cottical velocity fao in mls tlow rate 35m /s: (b) Determine the criti cad. depth of. the Floo in meters Dietormine the Specific cheroy in meter8

1. From the figure, determine a. Rx b. Ry c. Magnitude of Resultant d. The inclination of the resultant 30 kN 15 kN 70 S0 KN 30 60 33 KN 25 kN