Use assembly language to compute the following calculations ;; Byte Operations; unsigned byte additions;;;;; signed byte additions;;;************;;; unsigned byte subtractions.;bAns1 = bNum2 + bNum3= bNum1 + bNum3bAns2bans 3= bNum4 + bNum3;;bAns4 = bNum5 + bNum7bAns5=bNum6 + bNum8;; signed byte subtraction;bAns6 =bNuml - bNum3bAns7 =bNum2 - bNum3bNum4;bAns8bNum3;;; unsigned byte multiplication;;bAns9bNum5bNum8bAns10bNum7bNum6;; signed byte multiplication;wAns11=bNum1 * bNum4wAns12bNum2* bNum2wAns13 =bNum3* bNum2;;; unsigned byte division;;;wAns14 = bNum5bNum6wAns15 = bNum7 * bNum8;; signed byte division;;bAns16bNum1 / bNum3bAns17=bNum4 / bNum2bAns18 wNum3 / bNum4bRem18 wNum3 % bNum4bAns19bNum5 / bNum8bAns20 bNum6/bNum7bAns21wNum5/bNum8bRem21wNum5 % bNum8; ******; Word Operations; unsigned word additions;*************wAns1= wNum4 + wNum1wAns2= wNum3 + wNum2wAns3= wNum3 + wNum3;;; signed word additions;**********************wAns4 = wNum5 + wNum7wAns 5 = wNum 6+ wNum8 ; unsigned word subtractionswAns6= wNum1 - wNum3wAns7= wNum2 - wNum4wAns8= wNum4 wNum2;;; signed word subtractionwAns9= wNum5wNum8wAns10= wNum6 wNum7;; unsigned word multiplication;;; signed word multiplicationdAns11wNum1wNum4dAns12= wNum4* wNum4dAns13= wNum2 * wNum3; unsigned word division;;dAns14= wNum5* wNum7dans 15 = wNum6wNum8; signed word division***;wAns16= wNum2 / WNum3wAns17= wNuml/wNum4wAns18 dNuml/wNum2wRem 18 dNum1 % wNum2wAns19= wNum5/ wNum8wAns20= wNum7/WNum6wAns21 dNum5/ wNum7wRem21 dNum5 % wNum7;; Double-Word Operations; unsigned double-word additionsdAns1 =dNum1dAns2dans 3dNum4= dNum2 + dNum3dNum 3 + dNum4; signed double-word additionsdAns4 = dNum 5 + dNum8dans 5 dNum6 + dNum7; unsigned double-word subtractionsdAns6 = dNum1dNum4dAns7 = dNum2- dNum3dans 8 dNum3-dNum4; signed double-word subtractiondAns9dNum5 - dum7dAns10 = dNum 6 - dNum8; unsigned double-word multiplicationqAns11=dNum1 dNum2qAns12 dNum3 dNum4qAns13 dNum2 * dNum3; signed double-word multiplicationqAns14dNum 5dNum6qAns15 = dNum7 * dNum8; unsigned double-word divisiondAns16 dNum1 / dNum4dAns17 dNum2 dNum3

Byte operations in assembly language involve manipulating data stored in 8-bit units. Word…

***** ; ; Byte Operations ; unsigned byte additions bAnsl bAns2 bAns3 ; signed byte additions bAns4 bAns5 =bNum2 + bNum3 =bNum1 + bNum3 =bNum4 + bNum3 ‒‒‒‒‒ unsigned byte subtractions =bNum5+ bNum7 =bNum6 + bNum8 bAns6 =bNum1bNum3 bAns7 =bNum2bNum3 bAns8 =bNum3bNum4 ; signed byte subtraction bAns9 =bNum5bNum8 bAns10 bNum7bNum6 ; unsigned byte multiplication wAns11 =bNum1 bNum4 wAns12 =bNum2 bNum2 wAns13 =bNum3 * bNum2 ; signed byte multiplication wAns14 =bNum5bNum6 wAns15 =bNum7bNum8 unsigned byte division bAns16bNum1/bNum3 bAns17 bNum4 bNum2 bAns18= wNum3 / bNum4 bRem18 WwNum3 8 bNum4 signed byte division bAns19bNum5/ bNum8 *********** bAns20 bNum6/bNum7 bAns21= wNum5/bNum8 bRem21= wNum5 % bNum8 ; Word Operations ; unsigned word additions wAns1 wAns2 wAns3 =wNum4 + wNum1 =wNum3 + wNum2 =wNum3 + wNum3 signed word additions wAns4 =wNum5 + wNum7 wAns5 =wNum6 wNum8 *******

***** ; ; Byte Operations ; unsigned byte additions bAnsl bAns2 bAns3 ; signed byte additions bAns4 bAns5 =bNum2 + bNum3 =bNum1 + bNum3 =bNum4 + bNum3 ‒‒‒‒‒ unsigned byte subtractions =bNum5+ bNum7 =bNum6 + bNum8 bAns6 =bNum1bNum3 bAns7 =bNum2bNum3 bAns8 =bNum3bNum4 ; signed byte subtraction bAns9 =bNum5bNum8 bAns10 bNum7bNum6 ; unsigned byte multiplication wAns11 =bNum1 bNum4 wAns12 =bNum2 bNum2 wAns13 =bNum3 * bNum2 ; signed byte multiplication wAns14 =bNum5bNum6 wAns15 =bNum7bNum8 unsigned byte division bAns16bNum1/bNum3 bAns17 bNum4 bNum2 bAns18= wNum3 / bNum4 bRem18 WwNum3 8 bNum4 signed byte division bAns19bNum5/ bNum8 ***** bAns20 bNum6/bNum7 bAns21= wNum5/bNum8 bRem21= wNum5 % bNum8 ; Word Operations ; unsigned word additions wAns1 wAns2 wAns3 =wNum4 + wNum1 =wNum3 + wNum2 =wNum3 + wNum3 signed word additions wAns4 =wNum5 + wNum7 wAns5 =wNum6 wNum8 *

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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