By using variation of parameters, determine the general solution of ty" - 3ty + 4y = t² lnt, t > 0 given that y(t) = t², y(t) = t² Int constitute a fundamental set of solutions of the homogeneous equation. Remark: the corresponding homogeneous differential equation is an Euler equation and fits to item d) in exercise 1.

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Author:Erwin Kreyszig
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Chapter2: Second-order Linear Odes
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### Differential Equations: Variation of Parameters

**Problem Statement:**

By using variation of parameters, determine the general solution of the differential equation
\[
t^2y'' - 3ty' + 4y = t^2 \ln t, \quad t > 0
\]
given that \( y_1(t) = t^2 \), \( y_2(t) = t^2 \ln t \) constitute a fundamental set of solutions of the homogeneous equation.

**Remark:**
The corresponding homogeneous differential equation is an Euler equation and fits to item d) in exercise 1.

### Explanation:

This problem involves solving a second-order non-homogeneous linear differential equation using the method of variation of parameters. Here's a detailed breakdown of the steps involved:

1. **Homogeneous Equation:**
   \[
   t^2y'' - 3ty' + 4y = 0
   \]
   Given solutions:
   - \( y_1(t) = t^2 \)
   - \( y_2(t) = t^2 \ln t \)

2. **Non-Homogeneous Equation:**
   \[
   t^2y'' - 3ty' + 4y = t^2 \ln t
   \]

3. **Variation of Parameters Method:**
   To find the particular solution \( y_p(t) \) of the non-homogeneous equation, we assume:
   \[
   y_p(t) = u_1(t)y_1(t) + u_2(t)y_2(t)
   \]
   where \( u_1(t) \) and \( u_2(t) \) are functions to be determined.

4. **Determining \( u_1(t) \) and \( u_2(t) \):**
   These functions satisfy the following system of equations:
   \[
   \begin{cases}
   u_1'(t)y_1(t) + u_2'(t)y_2(t) = 0 \\
   u_1'(t)y_1'(t) + u_2'(t)y_2'(t) = \frac{g(t)}{W(y_1, y_2)}
   \end{cases}
   \]
   where \( W(y_1, y_2) \) is the Wronskian of \( y_1
Transcribed Image Text:### Differential Equations: Variation of Parameters **Problem Statement:** By using variation of parameters, determine the general solution of the differential equation \[ t^2y'' - 3ty' + 4y = t^2 \ln t, \quad t > 0 \] given that \( y_1(t) = t^2 \), \( y_2(t) = t^2 \ln t \) constitute a fundamental set of solutions of the homogeneous equation. **Remark:** The corresponding homogeneous differential equation is an Euler equation and fits to item d) in exercise 1. ### Explanation: This problem involves solving a second-order non-homogeneous linear differential equation using the method of variation of parameters. Here's a detailed breakdown of the steps involved: 1. **Homogeneous Equation:** \[ t^2y'' - 3ty' + 4y = 0 \] Given solutions: - \( y_1(t) = t^2 \) - \( y_2(t) = t^2 \ln t \) 2. **Non-Homogeneous Equation:** \[ t^2y'' - 3ty' + 4y = t^2 \ln t \] 3. **Variation of Parameters Method:** To find the particular solution \( y_p(t) \) of the non-homogeneous equation, we assume: \[ y_p(t) = u_1(t)y_1(t) + u_2(t)y_2(t) \] where \( u_1(t) \) and \( u_2(t) \) are functions to be determined. 4. **Determining \( u_1(t) \) and \( u_2(t) \):** These functions satisfy the following system of equations: \[ \begin{cases} u_1'(t)y_1(t) + u_2'(t)y_2(t) = 0 \\ u_1'(t)y_1'(t) + u_2'(t)y_2'(t) = \frac{g(t)}{W(y_1, y_2)} \end{cases} \] where \( W(y_1, y_2) \) is the Wronskian of \( y_1
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