By using the Laplace transform to solve the system x' = 3x - 3y + 2 We obtain: * None of them {y'²=-6x-t x(t)=[1/108] (133e^5t-28e^(-2t)+3-18t) and y(t)=[-1/108] (133e^6t+56e^5t+18t-81) x(t)=[1/108] (133e^6t-28e^(-3t)+3-18t) and y(t)=[-1)/108] (133e^6t+56e^(-3t)+18t-81) x(t)=[1/108] (133e^6t+8e^(-3t)+3-18t) and -¹ (5³) = y(t)=[-1/108](133e^6t+5e^(-3t)+8t-81) t^(6)/36 t^(5)/24 x(0) = 1 y(0) = -1 None of them t^(4)/6

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