By using diff the fourier transform (jw) ² xlwo) = -₁. ejw 2 2سلم- (j)² w²x1w) = ~ejw2 W2 is ما 2 تم . +2+ -j24 +2+e 20زم_ j20- 2 + √24 How did he get the value inside the circle
By using diff the fourier transform (jw) ² xlwo) = -₁. ejw 2 2سلم- (j)² w²x1w) = ~ejw2 W2 is ما 2 تم . +2+ -j24 +2+e 20زم_ j20- 2 + √24 How did he get the value inside the circle
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Question
i need the answer quickly
![Now, 2 x (+)
dt'
50.
+
d2x(+)
dt 2
d2 x (1)
dt 2
is
+2
(jj²w² x 1w) =
d2x(+)
ct 2
1+1
= ~15 (t + 2) + 25 (1-0) + 1 5 (t-1)
= -√(x + 2) + 25H) + 5 (+-2)
+2
-ej w 2
W 2
By using differentiation in time domain property,
the fourier transform
jw2
(jw) ² x 120) = -1.e
+2+
20 نتم
-j240
t
+2+e
2 + √24
-pj2w]
How did he get the
value inside the circle
I](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F3ac236a9-a598-46ac-b693-d692c3c5bb8a%2F79848b69-7335-4ac7-936d-8944706701fd%2F9kxop7_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Now, 2 x (+)
dt'
50.
+
d2x(+)
dt 2
d2 x (1)
dt 2
is
+2
(jj²w² x 1w) =
d2x(+)
ct 2
1+1
= ~15 (t + 2) + 25 (1-0) + 1 5 (t-1)
= -√(x + 2) + 25H) + 5 (+-2)
+2
-ej w 2
W 2
By using differentiation in time domain property,
the fourier transform
jw2
(jw) ² x 120) = -1.e
+2+
20 نتم
-j240
t
+2+e
2 + √24
-pj2w]
How did he get the
value inside the circle
I
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