By theorem, the determinant of any nxn matrix is the product of its eigenvalues. Use this theorem to show that an nxn matrix is singular (not invertible) if and only if it has at least one eigenvalue that is zero.
By theorem, the determinant of any nxn matrix is the product of its eigenvalues. Use this theorem to show that an nxn matrix is singular (not invertible) if and only if it has at least one eigenvalue that is zero.
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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![By theorem, the determinant of any nxn matrix is the product of its eigenvalues.
Use this theorem to show that an nxn matrix is singular (not invertible) if and
only if it has at least one eigenvalue that is zero.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F51c20b90-f64e-4c68-84a5-d214462ac1df%2F5da9ea13-61c9-4e02-b941-e4e6b31658bb%2Fwpafugf_processed.jpeg&w=3840&q=75)
Transcribed Image Text:By theorem, the determinant of any nxn matrix is the product of its eigenvalues.
Use this theorem to show that an nxn matrix is singular (not invertible) if and
only if it has at least one eigenvalue that is zero.
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