By the alternating series test, the series 4(−1)k+1 k(k + 8) 4 k(k+8) First find the partial fraction decomposition of 4 k(k+8) Then find the limit of the partial sums. k+1 4(−1)k k(k + 8) k=1 Enter your answer for the sum as a reduced fraction. converges. Find its sum.

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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By the alternating series test, the series
k=1
4(−1)k+1
k(k + 8)
4
k(k+8)
First find the partial fraction decomposition of
4
k(k+ 8)
Then find the limit of the partial sums.
k+1
4(-1)^
k(k + 8)
k=1
Enter your answer for the sum as a reduced fraction.
converges. Find its sum.
Transcribed Image Text:By the alternating series test, the series k=1 4(−1)k+1 k(k + 8) 4 k(k+8) First find the partial fraction decomposition of 4 k(k+ 8) Then find the limit of the partial sums. k+1 4(-1)^ k(k + 8) k=1 Enter your answer for the sum as a reduced fraction. converges. Find its sum.
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