By READING the R vs t graph shown below, determine R, & the mean life. R (x10¹¹ decays/min) 10+ 7.5 5. 2.5 t (min) 2. 4 6 8 10 Ro decays/min mean life
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- Using the differential equation model: (dN/dt) = -kN. (k>0) where N(t) = amount of 14C at time t, approximately how old is a fossil with 17 g of 14C if it initially possessed 45 g of ¹4c? (Note: assume half life of 14C to be 5700 years) Choose All Correct Answers Below (A) 7650 years B) 8005 years C) 5792 years D 9430 years 1012 years 9622 yearsQue. 234 u has time Constant Lax105 year. How long will it take to Sample (8.s x105) 234U nuelei to (1-7x109/234. redueeThe half-life for the decay of carbon-14 is 5.73*10^3 years. Suppose the activity due to the radioactive decay of the carbon-14 in a tiny sample of an artifact made of wood from an archeological dig is measured to be 65. Bq. The activity in a similar-sized sample of fresh wood is measured to be 69. Bq. Calculate the age of the artifact. Round your answer to 2 significant digits
- Estimate up to three demical placesThe half life for the decay of carbon-14 is 5.73*10^3 years. Suppose the activity due to the radioactive decay of the carbon-14 in a tiny sample of an artifact made of wood from an archeological dig is measured to be 65. Bq. The activity in a similar-sized sample of fresh wood is measured to be 72. Bq. Calculate the age of the artifact. Round your answer to 2 significant digitsA) How much mass is left in a piece of animal skin after 17,145 years when a newly made piece of leather about the same size contains approximately 5603g of C-14? The half-life of C-14 is 5,715 years. B)How many years old is a piece of fossilized charcoal if the fossil contains 13.289g of C-14 when a new piece of charcoal of similar size contains 6803.9g? The half-life of C-14 is 5,715 years.
- i can confirm answer 5118 years is wrongRADIOACTIVITY. LAW OF RADIOACTIVE DECAY Activity units: 1 Ci = 3.7 × 1010 Bq 1. Nuclear decay law: N = Noe-at, The law of radioactive decay gives the quantitative relationship between the original number of nuclei present at time zero No and the number N at a later time t (sec), where e = 2.71828... is the base of the natural logarithm, and 2 is the decay constant for the nuclide (1/s). 2. Relationship between decay constant 1 and isotop half-life T1/2: 0.693 1= In(2) Radioisotope Half-life Modality T1/2 where å is decay constant (1/s), T1/2 is isotope half- life (s). T1/2 Carbon-11 20 minutes PET Fluorine-18 110 minutes PET Copper-64 12.7 hours PET 3. Activity or decay rate of a radioactive source A: Gallium-67 AN A = = AN 78.3 hours SPECT Gallium-68 68 minutes PET Technetum-99m 6.02 hours SPECT Δt where A is activity or decay rate of a radioactive source (Bq), N is number of nuclei present at time t Thallum-201 (s ), 2 is decay constant (1/s). 4. Activity A of a radioactive source at…Please help me answer the following.
- RADIOACTIVITY. LAW OF RADIOACTIVE DECAY Activity units: 1 Ci = 3.7 × 1010 Bq 1. Nuclear decay law: N = Noe¬at, The law of radioactive decay gives the quantitative relationship between the original number of nuclei present at time zero No and the number N at a later time t (sec), where e = 2.71828... is the base of the natural logarithm, and 2 is the decay constant for the nuclide (1/s). 2. Relationship between decay constant 1 and isotop half-life T1/2: 0.693 T1/2 1= In(2) Half-life Modality Radioisotope T1/2 where a is decay constant (1/s), T1/2 is isotope half- life (s). Carbon-11 20 minutes PET Fluorine-18 110 minutes PET Copper-64 | 12.7 hours PET 3. Activity or decay rate of a radioactive source A: Gallium-67 AN A = At where A is activity or decay rate of a radioactive lodine-123 source (Bq), N is number of nuclei present at time t Thallium-201 (s ), 2 is decay constant (1/s). 78.3 hours SPECT | 68 minutes Gallium-68 Technetum-99m PET 6.02 hours SPECT Indium-111 | 67.3 hours SPECT…Each time you dumped the pennies, one half-life passed; it has been shown that thehalf-life for this radioactive isotope is 20 years. In the year 2000, an archaeology teamunearths pottery and is using this isotope for radiometric dating to place the age of thepottery. It is shown that 95% of the nuclei have decayed. Using your graph,approximately how long ago was the pottery made?RADIOACTIVITY. LAW OF RADIOACTIVE DECAY Activity units: 1 Ci = 3.7 × 101º Bq 1. Nuclear decay law: N = Noe¬at, The law of radioactive decay gives the quantitative relationship between the original number of nuclei present at time zero No and the number N at a later time t (sec), where e = 2.71828... is the base of the natural logarithm, and 2 is the decay constant for the nuclide (1/s). 2. Relationship between decay constant 2 and isotop half-life T1/2: In(2) 0.693 Radioisotope Half-life Modality T1/2 T1/2 Carbon-11 20 minutes PET where a is decay constant (1/s), T1/2 is isotope half- life (s). 3. Activity or decay rate of a radioactive source A: ΔΝ Fluorine-18 110 minutes PET Copper-64 12.7 hours PET Gallium-67 78.3 hours SPECT Gallium-68 68 minutes PET = AN Technetum-99m 6.02 hours SPECT Δt where A is activity or decay rate of a radioactive source (Bq), N is number of nuclei present at time t (s ), 1 is decay constant (1/s). 4. Activity A of a radioactive source at a time t:…
