By Laws of Expected Value and Variance, determine E(Z) and V(Z) if Z = 4X + 1. A EZ) = 4E(X) + 1 and V(Z) = 16V(X) %3D B E(Z) = 4E(X) + 1 and V(Z) = 4V(X) %3D E(Z) = 4E(X) + 4 and V(Z) = 4V(X) E(Z) = 4E(X) + 4 and V(Z) = 16V(X) %3D

A First Course in Probability (10th Edition)
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ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
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By Laws of Expected Value and Variance, determine E(Z) and V(Z) if Z = 4X + 1.
E(Z) = 4E(X) + 1 and V(Z) = 16V(X)
E(Z) = 4E(X) + 1 and V(Z) = 4VX)
E(Z) = 4E(X) + 4 and V(Z) = 4V(X)
E(Z) = 4E(X) + 4 and V(Z) = 16V(X)
Transcribed Image Text:By Laws of Expected Value and Variance, determine E(Z) and V(Z) if Z = 4X + 1. E(Z) = 4E(X) + 1 and V(Z) = 16V(X) E(Z) = 4E(X) + 1 and V(Z) = 4VX) E(Z) = 4E(X) + 4 and V(Z) = 4V(X) E(Z) = 4E(X) + 4 and V(Z) = 16V(X)
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