By how much does a 65.0 climber stretch her 0.800 rope when she hangs 35.0 m below a rock outcropping? (For nylon, Y = 1.35 × 10⁹ Pa.) kg mountain cm diameter nylon -
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A: −36i+(−18)j+(−36)kExplanation:For any query with the solution, please ask in the comment box.
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Q: ) if A = = 3i+4j +2K and B= -2i +6j +5k find A. В. (A.B änjö a)
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