By how many times does the sample size have to be increased to decrease the margin of error by a factor of 6 The sample size must be increased by a factor of to decrease the margin of error by a factor of (Type a whole number.) What is the general relationship, if any, between the sample size and the margin of error? O A. Increasing the sample size by a factor M results in the margin of error decreasing by a factor of M В. Increasing the sample size by a factor M results in the margin of error decreasing by a factor of M 1 Increasing the sample size by a factor M results in the margin of error decreasing by a factor of M2 O D. There is no relationship between the sample size and the margin of error.

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**Question:**  
By how many times does the sample size have to be increased to decrease the margin of error by a factor of \( \frac{1}{6} \)?

---

**Solution:**  

The sample size must be increased by a factor of \(\underline{\quad}\) to decrease the margin of error by a factor of \( \frac{1}{6} \).  
(Type a whole number.)

**What is the general relationship, if any, between the sample size and the margin of error?**

- **Option A:**  
  Increasing the sample size by a factor \( M \) results in the margin of error decreasing by a factor of \( \frac{1}{M} \).
  
- **Option B:**  
  Increasing the sample size by a factor \( M \) results in the margin of error decreasing by a factor of \( \frac{1}{\sqrt{M}} \).
  
- **Option C:**  
  Increasing the sample size by a factor \( M \) results in the margin of error decreasing by a factor of \( \frac{1}{M^2} \).
  
- **Option D:**  
  There is no relationship between the sample size and the margin of error.

---

**Explanation:**  
Typically, the margin of error (ME) is inversely proportional to the square root of the sample size (n), which means \( ME \propto \frac{1}{\sqrt{n}} \). Thus:

- To decrease the margin of error by a factor of \( \frac{1}{6} \), the sample size must be increased by a factor of \( 6^2 = 36 \).

The correct answer would be based on this understanding, which aligns with **Option B** as the most parsimonious reasoning.
Transcribed Image Text:**Question:** By how many times does the sample size have to be increased to decrease the margin of error by a factor of \( \frac{1}{6} \)? --- **Solution:** The sample size must be increased by a factor of \(\underline{\quad}\) to decrease the margin of error by a factor of \( \frac{1}{6} \). (Type a whole number.) **What is the general relationship, if any, between the sample size and the margin of error?** - **Option A:** Increasing the sample size by a factor \( M \) results in the margin of error decreasing by a factor of \( \frac{1}{M} \). - **Option B:** Increasing the sample size by a factor \( M \) results in the margin of error decreasing by a factor of \( \frac{1}{\sqrt{M}} \). - **Option C:** Increasing the sample size by a factor \( M \) results in the margin of error decreasing by a factor of \( \frac{1}{M^2} \). - **Option D:** There is no relationship between the sample size and the margin of error. --- **Explanation:** Typically, the margin of error (ME) is inversely proportional to the square root of the sample size (n), which means \( ME \propto \frac{1}{\sqrt{n}} \). Thus: - To decrease the margin of error by a factor of \( \frac{1}{6} \), the sample size must be increased by a factor of \( 6^2 = 36 \). The correct answer would be based on this understanding, which aligns with **Option B** as the most parsimonious reasoning.
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