By Euler's formulae eia = cos a + i sin a and substitute in the above equation. 00 U (a, 0) = (cos ax + i sin ax) dx 0- 00 -|x| cos axdx + i e-lxl sin axdx -00 -00 00 cos axdx + 0 -00 00 -|x| e cos axdx -00

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I don't understand why the integral from -infinity to infinity of e^-abs(x)sinaxdx=0. Can you please explain it to me. Thank you 

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Math / Bundle: Differential Equations with Boundary-... | In Problems 1-21 and 24-26 use the Fourier integral transforms of ...
: In Problems 1-21 and 24-26 use the Fourier integral transforms of this section to solv...
Take Fourier transform of the above equation and solve as follows.
F {u (x, 0)} = F {e-lkl}
00
U (α, 0)
e-lxl eiax dx
-00
By Euler's formulae eia
= cos a + i sin a and substitute in the above equation.
00
U (a, 0) = / e
(cos ax + i sin ax) dx
- 0
00
00
,-|x|
cos axdx + i
sin axdx
-00
-00
00
- /
e
cos axdx + 0
-00
-|x|
e
cos axdx
-00
The integration function of the above equation is odd function of x.
00
So, U (a, 0) = 2
cos axdx.
So, the equation is expressed as,
U (α, 0)
(3)
1+a?
Substitute t = 0 in equation (2),
U α, 0) -C.
(4)
Equate the equations (3) and (4) as follows.
c =
1+a?
Substitute the value of c in equation (2),
Transcribed Image Text:4:17 PM Thu May 13 * 21% I AA bartleby.com M G Goog G Google 1-21 and 24-... A Classwork fo... G akshata mud... mer Mem... = bartleby Q Search for textbooks, step-by-step explanatio... Ask an Expert Math / Bundle: Differential Equations with Boundary-... | In Problems 1-21 and 24-26 use the Fourier integral transforms of ... : In Problems 1-21 and 24-26 use the Fourier integral transforms of this section to solv... Take Fourier transform of the above equation and solve as follows. F {u (x, 0)} = F {e-lkl} 00 U (α, 0) e-lxl eiax dx -00 By Euler's formulae eia = cos a + i sin a and substitute in the above equation. 00 U (a, 0) = / e (cos ax + i sin ax) dx - 0 00 00 ,-|x| cos axdx + i sin axdx -00 -00 00 - / e cos axdx + 0 -00 -|x| e cos axdx -00 The integration function of the above equation is odd function of x. 00 So, U (a, 0) = 2 cos axdx. So, the equation is expressed as, U (α, 0) (3) 1+a? Substitute t = 0 in equation (2), U α, 0) -C. (4) Equate the equations (3) and (4) as follows. c = 1+a? Substitute the value of c in equation (2),
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