By dragging all of the statements from the left column to the right column below, display a complete calculation of ₂³(5 + 4x) dx using Riemann sums. Statements to choose from: Drag these statements to the right column. [²15 + (5+4x) dx = lim n-00 = lim n→∞ = lim n→∞0 = lim n→∞ lim n-00 = lim n→∞ 12 k=1 = lim [1/³ + 2/2 (2k − 1)] n→∞0 n k=1 k=1 k=1 f(xk) Ax 13 + 2) = 15 (1³n+ 2²/2 n²) [(5 + 4(2 + ½ (2k − 1))) ½] n 32 2k - [(13 + 2/12 (2k − 1)) 1/2] Your solution: Put the statements in order in this column and press the Submit Answers button.

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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By dragging all of the statements from the left column to the right column below, display a complete calculation of ₂2³ (5+4x)dæ using Riemann sums.
Statements to choose from: Drag these
statements to the right column.
[" (5 + 4x) dx
lim
n→∞0
lim
n→→∞0
n
lim
n→∞0
k=1
= lim
n→∞
lim (1³n+
13
n→→→∞0
n
= lim [13³ + 12/12 (2k-1)]
n→∞0
k=1
= lim
n→∞
n
n
k=1
k=1
13 + 2 = 15
13
(#2 [1] + 2/1/21
k=1
- 12/²2 n²)
f(xk) Ax
[(5 + 4(2 + ½ (2k − 1)))]
n
[2k - 1])
[(13 + ²/12 (2k − 1)) 1/2]
Your solution: Put the statements in order in
this column and press the Submit Answers
button.
Transcribed Image Text:By dragging all of the statements from the left column to the right column below, display a complete calculation of ₂2³ (5+4x)dæ using Riemann sums. Statements to choose from: Drag these statements to the right column. [" (5 + 4x) dx lim n→∞0 lim n→→∞0 n lim n→∞0 k=1 = lim n→∞ lim (1³n+ 13 n→→→∞0 n = lim [13³ + 12/12 (2k-1)] n→∞0 k=1 = lim n→∞ n n k=1 k=1 13 + 2 = 15 13 (#2 [1] + 2/1/21 k=1 - 12/²2 n²) f(xk) Ax [(5 + 4(2 + ½ (2k − 1)))] n [2k - 1]) [(13 + ²/12 (2k − 1)) 1/2] Your solution: Put the statements in order in this column and press the Submit Answers button.
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