By considering momentum changes for an individual molecule inside a rectangular box, derive an expression for PV in terms of molecular mass, the number of molecules, and mean square speed. Compare this to the ideal gas equation to show that the mean kinetic energy of a molecule is 1.5 kB
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A: Given : mass m= 2.23×10-26 kgvrms=1050 m/s Formula used to calculate vrms=3kTmAlso T=mV2rms3khere,…
Q: Four tanks A, B, C, and D are filled with monatomic ideal gases. For each tank, the mass of an…
A: mass( m) = 2×10-26 kg Vrms = 1100 m/s Formula used to calculate vrms=3kTmAlso T=mV2rms3khere, k=…
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Q: Four tanks A, B, C, and D are filled with monatomic ideal gases. For each tank, the mass of an…
A:
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A: Given v1 = 500 m/s V2 = 600 m/s V3 = 700 m/s V4 = 800 m/s V5 = 900 m/s
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A:
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A: (a) Apply the Ideal gas equation. PV = nRT T = PV/nR = [(1.60 ✕ 106)(0.00580)]/[(3.6)(8.3142)]…
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A: Given: Kinetic energy,E = 4070 J
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A: The formula vrms = √(3kbT/m) v2/v1 = √(3kbT2/m)/√(3kbT1/m) constant term will cancel out, so...…
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By considering momentum changes for an individual molecule inside a rectangular box, derive an expression for PV in terms of molecular mass, the number of molecules, and mean square speed. Compare this to the ideal gas equation to show that the mean kinetic energy of a molecule is 1.5 kB
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