By applying necessary substitutions, the differential equations to the left will be reduced to the differential equations to the right. Match these differential equations. dy +2e²lny dx=0 (Inx+ Arctany) dx X (Arcsin ²x + tan²y) dx √1-x² Arctany dy 1+y² =0 + Arcsinx tany sec2y dy=0 —em cscr cotx dx – (csc+e cscx}e- dy=0 - 2(x + 1)(x² + y² + 2x - 4y) dx + 2(y-2) (x²-y²=2x+4y) dy=0 A u² du + (uv+v²) dv=0 B. (u+v) du-u dv=0 C. (u+v) du-v dv=0 D. (u²-v²) du+uv dv=0 E. u dv+v² du=0 F. (u+v) dv+(u-v) du=0 G. (u+v) du+ (u-v) dv=0 H. (u²+v²) dv+uv du=0 1. (u²+v²) du+uv dv=0 J. v² du+ (u²+uv) dv=0 K. (u-v) du+v dv=0 L. v² dv+ (u²+uv) du=0 M. (u-v) du- v dv=0 N. (u+v) du-(u-v) dv=0 O. u² dv+v du=0

Calculus: Early Transcendentals
8th Edition
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Author:James Stewart
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Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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By applying necessary substitutions, the differential equations to the left will be reduced to the differential equations to the right. Match these
differential equations.
ydy +2e²lny dx=0
(Inx+ Arctany) dx
(Arcsin ²x + tan²y) dx
Arctany dy
1+y²
=0
+ Arcsinx tany sec²y dy=0
-2y
* -e-cscv coti di – (csc?x te cscie- dy=0
-
CSCX
✓2(x+1) (x² + y² + 2x - 4y) dx + 2(y-2) (x²-y²=2x+4y) dy=0
A. u² du+ (uv+v²) dv=0
B. (u+v) du- u dv=0
C. (u+v) du-v dv=0
D. (u²-v²) du+ uv dv=0
E. u dv + v² du=0
F. (u+v) dv+(u-v) du=0
G. (u+v) du+ (u-v) dv=0
H. (u²+v²) dv + uv du=0
1. (u²+v²) du+ uv dv=0
J. v² du+ (u²+ uv) dv=0
K. (u-v) du+v dv=0
L. v² dv + (u²+uv) du=0
M. (u-v) du- v dv=0
N. (u+v) du-(u-v) dv=0
O. u² dv+v du=0
Transcribed Image Text:By applying necessary substitutions, the differential equations to the left will be reduced to the differential equations to the right. Match these differential equations. ydy +2e²lny dx=0 (Inx+ Arctany) dx (Arcsin ²x + tan²y) dx Arctany dy 1+y² =0 + Arcsinx tany sec²y dy=0 -2y * -e-cscv coti di – (csc?x te cscie- dy=0 - CSCX ✓2(x+1) (x² + y² + 2x - 4y) dx + 2(y-2) (x²-y²=2x+4y) dy=0 A. u² du+ (uv+v²) dv=0 B. (u+v) du- u dv=0 C. (u+v) du-v dv=0 D. (u²-v²) du+ uv dv=0 E. u dv + v² du=0 F. (u+v) dv+(u-v) du=0 G. (u+v) du+ (u-v) dv=0 H. (u²+v²) dv + uv du=0 1. (u²+v²) du+ uv dv=0 J. v² du+ (u²+ uv) dv=0 K. (u-v) du+v dv=0 L. v² dv + (u²+uv) du=0 M. (u-v) du- v dv=0 N. (u+v) du-(u-v) dv=0 O. u² dv+v du=0
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