By applying Kirchhoff's Voltage Law to a series RL circuit, we obtain the differential equation: di 4t+8 i=1, t>0 dt where i(t) = electrical current in Amperes, and t = time in seconds. 5-A) Use the integrating factor technique to find the expression of the current (general solution) 5-B) Use any other analytical technique to find the expression of the current (general solution) 5-C) Assuming that the current is 1 Amperes when t = 2 seconds, find the expression of the cur (particular solution) 5-D) Critically evaluate the obtained solution (expression of current) in transient and steady-stat regions. 5-E) The system changed so that the right-hand side of the differential equation is 0. Use the separation-of-variables technique to find the expression of the current (general solution).

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By applying Kirchhoff's Voltage Law to a series RL circuit, we obtain the differential equation:
di
4t+ 8 i = 1 , t>0
dt
where i(t) = electrical current in Amperes, and t = time in seconds.
5-A) Use the integrating factor technique to find the expression of the current (general solution)
5-B) Use any other analytical technique to find the expression of the current (general solution)
5-C) Assuming that the current is 1 Amperes when t = 2 seconds, find the expression of the cur
(particular solution)
5-D) Critically evaluate the obtained solution (expression of current) in transient and steady-stat
regions.
The system changed so that the right-hand side of the differential equation is 0. Use the
separation-of-variables technique to find the expression of the current (general solution).
5-E)
Transcribed Image Text:By applying Kirchhoff's Voltage Law to a series RL circuit, we obtain the differential equation: di 4t+ 8 i = 1 , t>0 dt where i(t) = electrical current in Amperes, and t = time in seconds. 5-A) Use the integrating factor technique to find the expression of the current (general solution) 5-B) Use any other analytical technique to find the expression of the current (general solution) 5-C) Assuming that the current is 1 Amperes when t = 2 seconds, find the expression of the cur (particular solution) 5-D) Critically evaluate the obtained solution (expression of current) in transient and steady-stat regions. The system changed so that the right-hand side of the differential equation is 0. Use the separation-of-variables technique to find the expression of the current (general solution). 5-E)
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