A -3 3 Graph of f The graph of a differentiable function fis shown above for -3
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Question

Transcribed Image Text:C
-3
-2
-1 B0
1
2
3
Graph of f
The graph of a differentiable function fis shown above for -3<x5 3. The graph of fhas
horizontal tangent lines at x = -1, x =1, and x = 2. The areas of regions A, B, C, and D are 5, 4,
5, and 3, respectively. Let g be the antiderivative of f such that g(3) = 7.
(a) Find all values of x on the open interval -3<x< 3 for which the functiong has a relative
maximum. Justify your answer.
(b) On what open intervals contained in -3<x<3 is the graph of g concave up? Give a
reason for your answer.
g(x) +1
(c) Find the value of lim-
2.r
or state that it does not exist. Show the work that leads to
your answer.
(d) Let h be the function defined by h(x) = 3f(2x +1) +4. Find the value of h(x) dx.
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Follow-up Question
But the area under a curve is not positive if it's below the x-axis. Area can be negative when it is under the x-axis. Area is routinely negative when we find the area under a cure using integrals. Why would you say that the area cannot be negative?
Solution
Follow-up Question
Why isn't region B -4 instead of positive 4?
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