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But my question is why is the velocity V2 that is going = 0 when computing the velocity V3 that is going upwards using the conservation of energy? in short, why does my method 2 not get the same V3 as my method 1

But my question is why is the velocity V2 that is going = 0 when computing the velocity V3 that is going upwards using the conservation of energy? in short, why does my method 2 not get the same V3 as my method 1

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You drop a 15 g ball from a height of 1.5 m and it bounces to a height of 0.80 m. Determine the total impulse on the ball when it hits the floor. 

hi for the above question, i am able to obtain the answer using method 1 as shown in the picture. 

But my question is why is the velocity V2 that is going = 0 when computing the velocity V3 that is going upwards using the conservation of energy? in short, why does my method 2 not get the same V3 as my method 1

Q013-1에 method I -8 T's datein Įtve method 2 Vz = /2gh myha t Ź muz ? = mghs tmuz? %3D V3 = /2ghs 3.96mls %3D 9i = mV2 : 0-015KS.42 : 0-083 Pf > mV3 - 0-015X3.96 =0.0594 3.7mls j= -0-0594-0.0813 : -0.141 kgmls
Transcribed Image Text:Q013-1에 method I -8 T's datein Įtve method 2 Vz = /2gh myha t Ź muz ? = mghs tmuz? %3D V3 = /2ghs 3.96mls %3D 9i = mV2 : 0-015KS.42 : 0-083 Pf > mV3 - 0-015X3.96 =0.0594 3.7mls j= -0-0594-0.0813 : -0.141 kgmls
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