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• Briefly differentiate electric potential to electric potential energy Solve the electric potential of a dipole with the configuration as shown in the image below • Solve the electric field at point P due to the dipole from the calculated electric potential. (Use the fact that E = VV, where VV is the gradient of V and V i + + k in cartesian coordinates) (x.y) (-a,0) (+a,0) Figure 1: The electric dipole

• Briefly differentiate electric potential to electric potential energy Solve the electric potential of a dipole with the configuration as shown in the image below • Solve the electric field at point P due to the dipole from the calculated electric potential. (Use the fact that E = VV, where VV is the gradient of V and V i + + k in cartesian coordinates) (x.y) (-a,0) (+a,0) Figure 1: The electric dipole

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• Briefly differentiate electric potential to electric potential energy • Solve the electric potential of a dipole with the configuration as shown in the image below • Solve the electric field at point P due to the dipole from the calculated electric potential. (Use the fact that E VV, where VV is the gradient of V and V = 2i+2j+k in cartesian coordinates) 19 0 (x,y) (-a,0) (+a,0) +q Figure 1: The electric dipole
Transcribed Image Text:• Briefly differentiate electric potential to electric potential energy • Solve the electric potential of a dipole with the configuration as shown in the image below • Solve the electric field at point P due to the dipole from the calculated electric potential. (Use the fact that E VV, where VV is the gradient of V and V = 2i+2j+k in cartesian coordinates) 19 0 (x,y) (-a,0) (+a,0) +q Figure 1: The electric dipole
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