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• Briefly differentiate electric potential to electric potential energy
• Solve the electric potential of a dipole with the configuration as shown in the image below
• Solve the electric field at point P due to the dipole from the calculated electric potential. (Use
the fact that E
VV, where VV is the gradient of V and V = 2i+2j+k in cartesian
coordinates)
19
0 (x,y)
(-a,0)
(+a,0)
+q
Figure 1: The electric dipole

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