Breathing is cyclic and a full respiratory cycle from the beginning of inhalation to the end of exhalation takes about 5 s. The maximum rate of air flow into the lungs is about 0.5 L/s. This explains, in part, why the function f(t)=sin(2xt/5) has often been used to model the rate of air flow into the lungs. If inhalation occurs during the interval 0 st≤ 2.5, what is the average rate of air flow during inhalation? (Round your answer to two decimal places.)
Breathing is cyclic and a full respiratory cycle from the beginning of inhalation to the end of exhalation takes about 5 s. The maximum rate of air flow into the lungs is about 0.5 L/s. This explains, in part, why the function f(t)=sin(2xt/5) has often been used to model the rate of air flow into the lungs. If inhalation occurs during the interval 0 st≤ 2.5, what is the average rate of air flow during inhalation? (Round your answer to two decimal places.)
Chapter3: Functions
Section3.3: Rates Of Change And Behavior Of Graphs
Problem 1SE: Can the average rate of change of a function be constant?
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![Breathing is cyclic and a full respiratory cycle from the beginning of inhalation to the end of exhalation takes about 5 s. The maximum rate of air flow into the lungs is about 0.5 L/s. This explains, in part, why the function \( f(t) = \frac{1}{2} \sin \left(\frac{2\pi t}{5}\right) \) has often been used to model the rate of air flow into the lungs. If inhalation occurs during the interval \( 0 \leq t \leq 2.5 \), what is the average rate of air flow during inhalation? (Round your answer to two decimal places.)
\[ \boxed{\phantom{x}} \quad \text{L/s} \]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F25226f33-2fc3-40c9-94fe-a259b74d1925%2Fa164245f-a993-4edc-b14e-ce0e2bdefac2%2F0m3xc9a_processed.png&w=3840&q=75)
Transcribed Image Text:Breathing is cyclic and a full respiratory cycle from the beginning of inhalation to the end of exhalation takes about 5 s. The maximum rate of air flow into the lungs is about 0.5 L/s. This explains, in part, why the function \( f(t) = \frac{1}{2} \sin \left(\frac{2\pi t}{5}\right) \) has often been used to model the rate of air flow into the lungs. If inhalation occurs during the interval \( 0 \leq t \leq 2.5 \), what is the average rate of air flow during inhalation? (Round your answer to two decimal places.)
\[ \boxed{\phantom{x}} \quad \text{L/s} \]
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