Brand A :11 17 29 10 28 37 29 31 19 44 Brand B: 22 16 28 12 18 36 23 11 41 29 At the 0.01% significance level, conclude the mean numbers of calories per packet are different for these two brands of junk food? Assume that the calories per packet of junk food are normally distributed for each of the two brands. 1) Is there enough evidence to conclude that the mean amount of calories in Brand A is more than the mean of amount of calories in Brand B? Use a = 0.05 2) Construct 95% confidence interval for the difference in the mean amount of calories in these two brand. Explain.
Brand A :11 17 29 10 28 37 29 31 19 44 Brand B: 22 16 28 12 18 36 23 11 41 29 At the 0.01% significance level, conclude the mean numbers of calories per packet are different for these two brands of junk food? Assume that the calories per packet of junk food are normally distributed for each of the two brands. 1) Is there enough evidence to conclude that the mean amount of calories in Brand A is more than the mean of amount of calories in Brand B? Use a = 0.05 2) Construct 95% confidence interval for the difference in the mean amount of calories in these two brand. Explain.
A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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Transcribed Image Text:Brand A : 11
17
29
10
28
37
29
31
44
19
Brand B: 22 16
28
12
18
36
23
11
41
29
At the 0.01% significance level, conclude the mean numbers of calories per packet are
different for these two brands of junk food? Assume that the calories per packet of junk
food are normally distributed for each of the two brands.
1) Is there enough evidence to conclude that the mean amount of calories in Brand A is
more than the mean of amount of calories in Brand B? Use a = 0.05
2) Construct 95% confidence interval for the difference in the mean amount of calories
in these two brand. Explain.
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