Bradford technique
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- Bradford technique makes use of the Coomassie blue dye that binds to the protein, with the complex absorbing strongly at 465 nm. A. True B. FalseConsider the following properties of the protein components of a sample mixture as provided in the table below: 1. if the mixture is subjected to gel filtration chromotography which protein component elute first? 2. if the mixture is subjected to isoelectric focusing which protein will stop m oving nearest to the positive electrode? 3. if the mixture is subjected to cation-exchange chromotography using a buffer at ph 7 which protein will bind to the resin? 4.if the mixture is subjected to SDS-PAGE which protein will be at bottomost portion of gel? 5.if the mixture is subjected to hydrophobic interaction chromotography which protein will bind most strongly to the resin?Protein analysis by gel electrophoresis a). Using the gel image provided to calculate the electrophoretic relative mobility as a ratio of the distance of protein migration to the distance of the tracking dye migration (See Appendix B). If your dye front is not visible, measure the mobility relative to the bottom edge of the resolving gel. Include a labeled print-out of your gel image with your report. b). Plot log MW of the protein markers and commercial myoglobin vs. mobility. Determine the molecular weight of myoglobin obtained after the final purification step (Sample E) from the equation of the line. Submit a copy of your graph along with the gel image. c). Compare your sample E and commercial myoglobin with the ladder. Summary your results. order of sample (left to right) is : A B C D blank E blank Commercial Myoglobin Molecular Ladder
- .A protein gives a single band on SDS gel electrophoresis, as shown in lanes 1 and 2 below. There is little if any effect from addingElectrophoresis A protein required 6.8 min to travel 82 cm to the detector in a 96 cm -long capillary tube with 25.4 kV between the ends. Find the apparent electrophoretic mobility.The movements of single motor-protein moleculescan be analyzed directly. Using polarized laser light, it ispossible to create interference patterns that exert a cen-trally directed force, ranging from zero at the center to afew piconewtons at the periphery (about 200 nm from thecenter). Individual molecules that enter the interferencepattern are rapidly pushed to the center, allowing them tobe captured and moved at the experimenter’s discretion.Using such “optical tweezers,” single kinesin mol-ecules can be positioned on a microtubule that is fixed toa coverslip. Although a single kinesin molecule cannotbe seen optically, it can be tagged with a silica bead andtracked indirectly by following the bead (Figure Q16–3A).In the absence of ATP, the kinesin molecule remains at thecenter of the interference pattern, but with ATP it movestoward the plus end of the microtubule. As kinesin movesalong the microtubule, it encounters the force of the inter-ference pattern, which simulates the load…
- Consider the following protein mixture: Protein A B C D Molecular Weight (kDa) 50 150 200 350 Affinity to Metal ion === Zn²+ === 1. Using hydrophobic interaction chromatography, the protein that will be eluted last is [Select] 2. Using affinity chromatography, the protein that will be eluted last in a Zn²+-containing column is 3. The protein with the fastest migration towards the anode in SDS-PAGE is [Select] IpH value 7 3 9 5 [Select] [Select] 4. Using a buffer solution with a pH of 4, the protein that will bind to an anion exchanger is 5. The protein that will be eluted last in a gel filtration column is [Select] 6. Using isoelectric focusing, the protein that will have a protein band nearest to the cathode (negative electrode) is [Select] % Hydrophobicity 20 45 75 55How many copies of a protein need to be presentin a cell in order for it to be visible as a band on an SDSgel? Assume that you can load 100 μg of cell extract ontoa gel and that you can detect 10 ng in a single band by sil-ver staining the gel. The concentration of protein in cellsis about 200 mg/mL, and a typical mammalian cell has avolume of about 1000 μm3 and a typical bacterium a vol-ume of about 1 μm3. Given these parameters, calculatethe number of copies of a 120-kd protein that would needto be present in a mammalian cell and in a bacterium inorder to give a detectable band on a gel. You might try anorder-of-magnitude guess before you make the calcula-tions.(a) 1 Normalized fluorescence 0.8 0.6 0.4 0.2 0 50 55 OM 0.100 M 0.200 M 0.300 M 0.500 M 1.00 M 2.00 M 60 113588 65 Temp. (°C) 70 75 80 Where is fully folded protein? • Where is fully unfolded protein? • Where is partially folded protein? • To what does SYPRO orange bind? • Why does fluorescence increase as a function of temperature? ● Define a melting temperature for a protein. • Demonstrate how an estimated melting temperature of the protein in zero molar ligand can be determined. • What is the effect of increasing the molar concentration on melting temperature for this protein? • Why is melting temperature a useful measurement to make for a protein especially if you are interested in protein aggregation?
- A protein gives a single band on SDS gel electrophoresis, as shown inlanes 1 and 2 below. There is little, if any, effect from adding β-mercaptoethanol (BME) to the sample; if anything, the protein runs a little bitslower. When treated with the proteolytic enzyme thrombin and electrophoresis in the absence of BME, the protein migrates a bitmore rapidly (lane 3). But if BME is present, two much more rapidlymigrating bands are found (lane 4). Explain these results in terms of amodel for the protein.Suppose that you are tasked to determine the protein concentration of an unknown protein solution via Bradford assay. You prepared six solutions of bovine serum albumin (BSA) with different concentrations. The initial concentration of the BSA stock solution is 7.50 mg/mL. Approximately 200 µL of Bradford Reagent was added to each of these solutions and the absorbance at 595 nm was taken after 5 minutes. See the table below for data on the standard solutions. Standard # A595 BSA conc (mg/mL) 0.000 0.158 2 1.125 0.291 2.250 0.372 4 3.375 0.503 5 4.500 6 5.625 0.675 Determine the protein concentration, in mg/mL, of the unknown solution if its absorbance at 595 nm was 0.248. Note: Final answer format must be x.xx (two decimal places). Round off only in the final answer. Do not round off in the middle of calculation.= A different Fab fragment binds to lysozyme with a dissociation constant of Ka 10-6 M. A 1 nM (10-9 M) solution of lysozyme is treated with increasing concentrations of this Fab fragment. At what concentration of added Fab will half of the lysozyme be bound to this Fab? [F] = ab M