Br, NH, NH, CH,Br H2, Pd (а) (b) CH3 H.

Chemistry
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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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Give the product (b) of the synthesis shown.

**Transcription for an Educational Website**

### Matching Reactions and Compounds

Below are three substances labeled I, II, and III, with their corresponding reactions. Match them to their respective stages in the reaction process:

- **A:** I
- **B:** II
- **C:** III

### Reaction Diagram

The diagram illustrates a series of chemical reactions involving the transformation of compounds:

1. **Compound I**:
   - Structure: Phenylacetylene (C₆H₅C≡CH)
   - Undergoes reaction with Br₂ to form an intermediate.

2. **Compound II**:
   - Structure: Phenylacetylene derivative (C₆H₅C≡CCH₂)
   - Reacts with an amine group (NH₂⁻) as indicated by the arrow labeled (a), yielding Compound I.

3. **Compound III**:
   - Structure: Methylbenzene derivative (C₆H₅CH₂CH₃, with an alkyl group)
   - Formed by the reaction of Compound II with CH₃Br, followed by hydrogenation with H₂ over a palladium catalyst (Pd) as shown by arrow labeled (b).

Each step highlights the critical transformations facilitated by reactions with specific reagents, thereby converting the initial alkyne into a saturated hydrocarbon.
Transcribed Image Text:**Transcription for an Educational Website** ### Matching Reactions and Compounds Below are three substances labeled I, II, and III, with their corresponding reactions. Match them to their respective stages in the reaction process: - **A:** I - **B:** II - **C:** III ### Reaction Diagram The diagram illustrates a series of chemical reactions involving the transformation of compounds: 1. **Compound I**: - Structure: Phenylacetylene (C₆H₅C≡CH) - Undergoes reaction with Br₂ to form an intermediate. 2. **Compound II**: - Structure: Phenylacetylene derivative (C₆H₅C≡CCH₂) - Reacts with an amine group (NH₂⁻) as indicated by the arrow labeled (a), yielding Compound I. 3. **Compound III**: - Structure: Methylbenzene derivative (C₆H₅CH₂CH₃, with an alkyl group) - Formed by the reaction of Compound II with CH₃Br, followed by hydrogenation with H₂ over a palladium catalyst (Pd) as shown by arrow labeled (b). Each step highlights the critical transformations facilitated by reactions with specific reagents, thereby converting the initial alkyne into a saturated hydrocarbon.
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