Bottom chord of truss is composed of two angle bars each having a dimension of 185 mm x 146 mm x 8.7 mm. Between them is a gusset plate, 9.5mm thick. At each end of joints, four 19mm-dia. bolts are fastened along the gage line, having an edge distance of 44 mm and 59mm pitch. Use A36 steel Fy 248 MPa Fu = 400 MPa %3D spacing of bolt = 68.9 mm %3D 9 5mm trick gunset plate edge dist Compute the capacity of the bottom chord based on block shear strength, in KN. uad

Bottom chord of truss is composed of two angle bars each having a dimension of 185 mm x 146 mm x 8.7 mm. Between them is a gusset plate, 9.5mm thick. At each end of joints, four 19mm-dia. bolts are fastened along the gage line, having an edge distance of 44 mm and 59mm pitch. Use A36 steel Fy 248 MPa Fu = 400 MPa %3D spacing of bolt = 68.9 mm %3D 9 5mm trick gunset plate edge dist Compute the capacity of the bottom chord based on block shear strength, in KN. uad

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Problem For the frame shown, design the maximum permissible value of P with a factor of safety of 2.5. Design the maximum permissible value of P based on the following conditions: ✓ Ultimate tensile strength of each member CD is 300 ksi Ultimate shear strength of the bolts in A, C, E, and F is 200 ksi ✓ Ultimate bearing strength of member BDE is 150 ksi ✓ Ultimate bearing strength of the support plates is 250 ksi Members CD and BDE have cross-sectional dimensions of 5 in x 3 in (the larger dimension is the width). The diameters of the bolts are as follows: A and B - 1.5 in: C and D-2 in E and F - 1 in. 1.5 in. thick Support Plates -2 ft + D 3 ft B 2 in thick Support Mate Solution Step 1. Identify the conditions for design. Stress normal stress in each member CD, OCD shear stress in bolt A, TA shear stress in bolt C, T shear stress in bolt E, T shear stress in bolt F, T bearing stress on member BDE due to: bolt B, BDE-B bolt D, OBDE-D bolt E, OBDE-E bearing stress on support plates at…
SITUATION I A lapped bolted lension member is shown. Diameter of bolts are 22 mm and the plate material is A36 steel Fy = 275 MPа, Fи 3 415 МPа. Assume the fasteners are adequate and do not control the tensile capacity. Diameter of hole is 2.5 mm bigger than the diameter of bolt. 12 :: 350 50 100 100 50 50 1. Determine the tensile capacity of the lapped joint based on gross area. a. 252.656 kN c. 866.250 kN b. 202.125 kN d. 693.000 kN 2. Determine the net Area for the tensile capacity of the lapped joint. а. 3318 тm? c. 5250 mm? b. 1554 mm? d. 1824 mm? 3. Determine the tensile capacity of the lapped joint based on the net area. a. 752.856 kN C. 866.250 kN b. 688.845 kN d. 1039.500 kN
A double-angle shape, 2L7 3 4 3 3⁄8, is used as a tension member. The twoangles are connected to a gusset plate with 7⁄8-inch-diameter bolts throughthe 7-inch legs, as shown in Figure P3.4-5. A572 Grade 50 steel is used.a. Compute the design strength.b. Compute the allowable strength.
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The tension member shown in Figure 3.4-2 is a PL 5/8 x 10, and the steel is A36. The bolts are 7/8-inch in diameter. a. Determine the design strength for LRFD. b. Determine the allowable strength for ASD. | 2" +|+| in seinefrinehich 9 оо SO
A double-angle shape is shown in the figure. The steel is A36, and the holes are for 1/2-inch-diameter bolts. Assume the Ae = 0.75An. Section 2L5 x 3 x16 LLBB Determine the allowable tensile strength for ASD. Select one: а. 52.1 b. 104.2 c. 87.8 d. 43.9
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