Bottles for room spr take six boxes of five samples are 15.43, 1 samples are 1.63,0. (R bar)
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- Cartons of Plaster are supposed to weigh exactly 32 ounces. Inspectors want to develop process control charts. They take five samples of six (4) boxes each and weigh them. Sample means (X-bar) are: 33.8, 34.6, 34.7, 34.1, and 34.2 respectively. Also, the corresponding ranges are: 1.1,0.3,0.4,0.7, and O.3, respectively. The lower and upper control limits of the R- chart are respectively O a. O and 0.15 Ob. 0.03 and 1.28 Oc. O and 1.28 O d. 0.01 and 1.13 O e. None is correctCartons of Plaster are supposed to weigh exactly 32 ounces. Inspectors want to develop process control charts. They take five samples of six (5) boxes each and weigh them. Sample means (X-bar) are: 33.8, 34.6, 34.7, 34.1, and 34.2 respectively. Also, the corresponding ranges are: 1.1, 0.3, 0.4, 0.7, and 0.3, respectively. The lower and upper control limits of the R-chart are ,respectively O a. None is correct O b. O and O.15 O c. 0.01 and 1.13 O d. 0.03 and 1.18 O e. O and 1.18Cartons of Plaster are supposed to weigh exactly 32 ounces. Inspectors want to develop process control charts. They take five samples of six (6) boxes each and weigh them. Sample means (X-bar) are: 33.8, 34.6, 34.7, 34.1, and 34.2 respectively. Also, the corresponding ranges are: 1.1, 0.3, 0.4, 0.7, and 0.3, respectively. The lower and upper control limits of the xbar-chart are respectively O a. 33.12 and 34.12 b. 34.01 and 34.55 O c. 30.11 and 40.15 O d. None is correct O e. 37.01 and 39.23
- Bottles for room spray are supposed to weigh exactly 16 oz. Inspectors want to develop process control charts. They take six boxes of five bottles each and weigh them. They obtain the following data. The mean weights of each of the 6 samples are 15.43, 14.47, 18.07, 17.34 12.74and 15.58 respectively. Likewise , the range values for the each of 6 samples are 1.63.0.66 6, 0.47, 0.40, 0.20 , and 0.90 respectivelyFind out Grand Mean double bar), and mean range (R bar) aligned 16.53,0.71\\ 15.82,.0.65 aligned a. b. Oc 16.538, 0.86 e. 0.0Bottles for room spray are supposed to weigh exactly 16 oz. Inspectors want to develop process control charts. They take five (05) boxes of four (04) bottles each and weigh them. They obtain the following data. The mean weights of each of the 05 samples are 15.2, 14.6,16.5,18.1, and 13.2 respectively. Likewise, the range values for the each of 05 samples are 0.4, 0.2, 0.4, 0.5, and 0.9 respectively. For the X-bar charts and R-charts, the Parameters, A2, D3 and D4 are respectively. Select one: a. 0.48, 0.00, 2.00 b. 0.25, 0.31, 1.69 c. 0.73, 0.00, 2.28 d. 0.37, 0.14, 1.86Auto pistons at Wemming Chung's plant in Shanghai are produced in a forging process, and the diameter is a critical factor that must be controlled. From sample sizes of 10 pistons produced each day, the mean and the range of this diameter have been as follows: a) What is the value of x? x= 156.76 mm (round your response to two decimal places). b) What is the value of R? Day 1 2 3 4 5 Mean x (mm) 158.9 155.2 155.6 157.5 156.6 R = 4.40 mm (round your response to two decimal places). c) What are the UCL and LCL using 3-sigma? Upper Control Limit (UCL) = mm (round your response to two decimal places). Range R (mm) 4.2 4.4 4.3 4.8 4.3 Ç
- Auto pistons at Wemming Chung's plant in Shanghai are produced in a forging process, and the diameter is a critical factor that must be controlled. From sample sizes of 10 pistons produced each day, the mean and the range of this diameter have been as follows: a) What is the value of x? = x= 156.76 mm (round your response to two decimal places). b) What is the value of R? R= mm (round your response to two decimal places). Day 1 2 3 4 5 Mean x (mm) 158.9 155.2 155.6 157.5 156.6 Range R (mm) 4.2 4.4 4.3 4.8 4.3Auto pistons at Wemming Chung's plant in Shanghai are produced in a forging process, and the diameter is a critical factor that must be controlled. From sample sizes of 5 pistons produced each day, the mean and the range of this diameter have been as follows: Day Mean (mm) Range R (mm) 158 4.3 151.2 4.4 155.7 4.2 153.5 4.8 156.6 4.5 What is the UCL using 3-sigma?(round your response to two decimal places). 1. 2. 4.The specifications for a gasket that installs between two engine parts calls for a thickness of 6.0 mm ± .2 mm. The standard deviation of the process is estimated to be 0.05 mm. The process is known to operate at a mean thickness of 6.1 mm What are the upper and lower specification limits for the gasket? What are the Cp and Cpk values for this process? Is this process capable of producing the desired part?
- A quality analyst wants to construct a sample mean chart for controlling a packaging process. Each day last week, he randomly selected four packages and weighed each. The raw data (in ounces) from that quality control activity appear below. Weight Day Package 1 Package 2 Package 3 Package 4 Monday 23 22 23 24 Tuesday 23 21 19 21 Wednesday 20 19 20 21 Thursday 18 19 20 19 Friday 18 20 22 20 What is the average of sample ranges in the random samples? Must compute each value in 2 dec pl.Using samples of 200 credit card statements, an auditor found the following: Sample 1 2 3 4 Number with errors 4 2 5 9 a. Determine the fraction defective in each sample. b. If the true fraction defective for this process is unknown, what is your estimate of it? c. What is your estimate of the mean and standard deviation of the sampling distribution of fractions defective for samples of this size? d. What control limits would give an alpha risk of .03 for this process? Page 457 e. What alpha risk would control limits of .047 and .003 provide? f. Using control limits of .047 and .003, is the process in control? g. Suppose that the long-term fraction defective of the process is known to be 2 percent. What are the values of the mean and standard deviation of the sampling distribution? h. Construct a control chart for the process, assuming a fraction defective of 2 percent, using two-sigma control limits. Is the process in control? Can you show me the steps and formulas using excelA metal fabricator produces connecting rods with an outer diameter that has a 1 ± 0.04 inch specification. A machine operator takes several sample measurements over time and determines the sample mean outer diameter to be 1.003 inches with a standard deviation of 0.020 inch. Calculate the process capability index.