Homework Help is Here – Start Your Trial Now!
Math
Probability
borderline, spin again. Find the probability that the pointer will stop on an odd number or a number less than 7. 7

borderline, spin again. Find the probability that the pointer will stop on an odd number or a number less than 7. 7

A First Course in Probability (10th Edition)
A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
See similar textbooks
icon
Related questions
Question
**Educational Website Content: Probability with Spinners** --- **Problem Description:** It is equally probable that the pointer on the spinner shown will land on any one of the eight regions, numbered 1 through 8. If the pointer lands on a borderline, spin again. Find the probability that the pointer will stop on an odd number or a number less than 7. **Spinner Description:** The spinner is divided into eight equal sections, each labeled with a number from 1 to 8. The numbers are arranged clockwise as follows: - 1 (yellow) - 2 (pink) - 3 (blue) - 4 (dark blue) - 5 (green) - 6 (light green) - 7 (orange) - 8 (light yellow) The spinner includes a pointer at its center, which can land on any of these numbered sections. **Solution:** To determine the probability, we need to identify the favorable outcomes: - Odd numbers: 1, 3, 5, 7 - Numbers less than 7: 1, 2, 3, 4, 5, 6 Combine these criteria to list unique favorable numbers: 1, 2, 3, 4, 5, 6, 7 Count the favorable numbers: 7 There are 8 possible outcomes altogether (numbers 1 through 8). Thus, the probability that the pointer will stop on an odd number or a number less than 7 is given by the ratio of favorable outcomes to the total number of outcomes: \[ \text{Probability} = \frac{7}{8} \] However, this example mistakenly shows the probability as \(\frac{3}{4}\), which might have been simplified incorrectly in a different context. *Note: Always cross-check to ensure correct interpretation when given probabilities.* --- For more detailed explanations on probabilistic concepts, continue exploring our educational resources on probability theory and statistics!
Transcribed Image Text:**Educational Website Content: Probability with Spinners** --- **Problem Description:** It is equally probable that the pointer on the spinner shown will land on any one of the eight regions, numbered 1 through 8. If the pointer lands on a borderline, spin again. Find the probability that the pointer will stop on an odd number or a number less than 7. **Spinner Description:** The spinner is divided into eight equal sections, each labeled with a number from 1 to 8. The numbers are arranged clockwise as follows: - 1 (yellow) - 2 (pink) - 3 (blue) - 4 (dark blue) - 5 (green) - 6 (light green) - 7 (orange) - 8 (light yellow) The spinner includes a pointer at its center, which can land on any of these numbered sections. **Solution:** To determine the probability, we need to identify the favorable outcomes: - Odd numbers: 1, 3, 5, 7 - Numbers less than 7: 1, 2, 3, 4, 5, 6 Combine these criteria to list unique favorable numbers: 1, 2, 3, 4, 5, 6, 7 Count the favorable numbers: 7 There are 8 possible outcomes altogether (numbers 1 through 8). Thus, the probability that the pointer will stop on an odd number or a number less than 7 is given by the ratio of favorable outcomes to the total number of outcomes: \[ \text{Probability} = \frac{7}{8} \] However, this example mistakenly shows the probability as \(\frac{3}{4}\), which might have been simplified incorrectly in a different context. *Note: Always cross-check to ensure correct interpretation when given probabilities.* --- For more detailed explanations on probabilistic concepts, continue exploring our educational resources on probability theory and statistics!
Expert Solution
steps

Step by step

Solved in 2 steps

SEE SOLUTIONCheck out a sample Q&A here
Blurred answer