he population proportion of 1943 adults who were total abstainers and p, represent the population proportion of recent adults who were total abstainersDetermine the null and alternative hypotheses.Ho: P1 V P2H,: P.V P2Find the test statistic for this hypothesis test.(Round to two decimal places as needed.)Determine the P-value for this hypothesis test.(Round to three decimal places as needed.)Interpret the P-value.If the population proportions areV one would expect a sample difference proportionV the one observed in about out of 100 repetitions of this experiment.(Round to the nearest integer as needed.)State the conclusion for this hypothesis test.O A. Do not reject Ho. There is sufficient evidence at the a= 0.05 level of significance to suggest the proportion of adults who totally abstain from alcohol has changed.O B. Do not reject Ho. There is not sufficient evidence at the a= 0.0level of significance to suggest the proportion of adults who totally abstain from alcohol has changed.O C. Reject Ho. There is not sufficient evidence at the a= 0.05 level of significance to suggest the proportion of adults who totally abstain from alcohol has changed.changed.O D. Reject Ho. There is sufficient evidence at the a=0.05 level of significance to suggest the proportion of adults who totally abstain from alcoholO Time Remai In 1943, an organization surveyed 1100 adults and asked, "Are you a total abstainer from, or do you on occasion consume, alcoholic beverages?" Of the 1100 adults surveyed, 429 indicated that they were total abstainers. In a recent survey the samequestion was asked of 1100 adults and 374 indicated that they were total abstainers. Complete parts (a) and (b) below.(a) Determine the sample proportion for each sample.The proportions of the adults who took the 1943 survey and the recent survey who were total abstainers are and respectively.(Round to three decimal places as needed(b) Has the proportion of adults who totally abstain from alcohol changed? Use the a=0.05 level of significance.First verify the model requirements. Select all that applyme sample size is more than 5% of the population size for each sample.C ne data come from a population that is normally distributed.OC nPi (1-P,) = 10 and n,º2 (1-p2) = 10OD. The samples are dependent.DE. The sample size is less than 5% of the population size for each sample.OF. The samples are independentIdentify the null and alternative hypotheses for this test. Let p, represent the population proportion of 1943 adults who were total abstainers and p, represent the population proportion of recent adults who were total abstainersDetermine the null and alternative hypotheses.Ho Pa V P2Hy P V P2Find the test statistic for this hypothesis test(Round to two decimal places as needed.)

Solution: Given N1=1100, X1=429 N2=1100, X2=374 (α)= 0.05 a) Ans is 0.39 and 0.34 b) Correct option is A,B,C,F (This are assumption) Hypothesis is test statistics is Test Statistics is 2.44 p-value calculate by using Excel =2*NORM.S.DIST(z , Cumulative) =2*NORM.S.DIST( 2.436 , TRUE) =0.0149 p-value is 0.015 Conclusion: since p = 0.015 <0.05, it is concluded that the null hypothesis is rejected. Therefore, there is enough evidence to claim that the population proportion is different than at α=0.05 significance level. so correct option is (D) Reject H0,There is sufficient evidance at the alpha=0.05levl of significance to suggest that population of adult who totally abstain from alcohol has changed