BOILING HEAT TRANSFER PROBLEM 2: Saturated water at Tsat=100C flows with a mass flow rate of m=0.1 kg/s through a 2.5x10-2 m ID vertical tube of L=5 m, subjected to a uniform wall temperature of Tw=110 C. Calculate the two phase heat transfer coefficient and total heat transfer.
BOILING HEAT TRANSFER PROBLEM 2: Saturated water at Tsat=100C flows with a mass flow rate of m=0.1 kg/s through a 2.5x10-2 m ID vertical tube of L=5 m, subjected to a uniform wall temperature of Tw=110 C. Calculate the two phase heat transfer coefficient and total heat transfer.
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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
Transcribed Image Text:BOILING HEAT TRANSFER
PROBLEM 2: Saturated water at Tsat=100 C flows with a mass flow rate of m=0.1 kg/s through a
2.5x10-2 m ID vertical tube of L=5 m, subjected to a uniform wall temperature of Tw=110 C. Calculate
the two phase heat transfer coefficient and total heat transfer.

Transcribed Image Text:Step 1
Soletion -> Gindy m = 0.1k(s Tsut = lo0'c , Tw = 110'c
m = 0.1s , Tsct = l0°c , Tw > 1o'c
D = 2 SX10?m ,L> 5M
incorrect
Step 2
: Q = m cp AT
fOR woty Cp = 4.2 kI
ng-k
4 |0)
= 0-1x 4.2 x (110-
= 4.2 kw
: a = hA AT
X 10
h = lo 69.51
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