Quickly, please. TinBoilerPh= 2000 [kPa]h3 = 3468 [kJ/kg]Wturb,outTurbine"pump.inST=0.85=1 Pumph4s = 2589 [KJ/kg)outCondenser P. = 50 [kPa]h = 340.5 [kJ/kg]V = 0.00103 [m/kg]Determine the thermal efficiency. All process are ideal, except the process in turbine for whlch Isentropic efficiency is given.

Solution; The specific pump work is calculated as : Wp=v1(P2-P1)=0.00103(2000-50)=2.0085 kJ/kg The…

Answered: Boiler Ph=2000 [kPa] h3 = 3468 [kJ/kg]…

Boiler Ph=2000 [kPa] h3 = 3468 [kJ/kg] Wturb,out Turbine "pump.in TST =0.85 =1 Pump T1sp h4s = 2589 [kJ/kg] 9out Condenser P.= 50 [KPa] h = 340.5 [kJ/kg] V = 0.00103 [m /kg]

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Conservation of Energy

In physics, the rule of the conservation of energy states that energy doesn’t disappear from the atmosphere; instead, it changes its form from one type to another. Energy is one of the most important physical quantities in nature, and it cannot be created or destroyed — only transformed.

Question

Quickly, please.

Tin
Boiler
Ph= 2000 [kPa]
h3 = 3468 [kJ/kg]
Wturb,out
Turbine
"pump.in
ST=0.85
=1 Pump
h4s = 2589 [KJ/kg)
out
Condenser P. = 50 [kPa]
h = 340.5 [kJ/kg]
V = 0.00103 [m/kg]
Determine the thermal efficiency. All process are ideal, except the process in turbine for whlch Isentropic efficiency is given.

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