body begins to cool. It has been determined experimentally that the constant in Newton's Law of Cooling is approxi- mately k Suppose that the temperature of the surroundings is 60°F. (a) Find a function T(t) that models the temperature t hours 0.1947, assuming that time is measured in hours. %3D after death. (b) If the temperature of the body is now 72°F, how long ago

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Precalculus:Modeling exponential functions
26. Time of Death Newton's Law of Cooling is used in homicide
investigations to determine the time of death. The normal
body temperature is 98.6 °F. Immediately following death, the
body begins to cool. It has been determined experimentally
that the constant in Newton's Law of Cooling is approxi-
mately k = 0.1947, assuming that time is measured in hours.
Suppose that the temperature of the surroundings is 60°F.
(a) Find a function T(t) that models the temperature t hours
after death.
(b) If the temperature of the body is now 72°F, how long ago
was the time of death?
Co a
Transcribed Image Text:26. Time of Death Newton's Law of Cooling is used in homicide investigations to determine the time of death. The normal body temperature is 98.6 °F. Immediately following death, the body begins to cool. It has been determined experimentally that the constant in Newton's Law of Cooling is approxi- mately k = 0.1947, assuming that time is measured in hours. Suppose that the temperature of the surroundings is 60°F. (a) Find a function T(t) that models the temperature t hours after death. (b) If the temperature of the body is now 72°F, how long ago was the time of death? Co a
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